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In the diagram above, O is the center of the circle

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Magoosh GMAT Instructor
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Kudos [?]: 2280 [0], given: 31

In the diagram above, O is the center of the circle [#permalink] New post 01 May 2013, 09:40
Expert's post
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

84% (01:44) correct 16% (00:49) wrong based on 44 sessions
Attachment:
circle with segments.png
circle with segments.png [ 14.94 KiB | Viewed 591 times ]

In the diagram above, O is the center of the circle, DC = a and DO = b. What is the area of the circle?

Statement #1: a^2 - 2ab + b^2 = 36

Statement #2: a + b = 22


For a discussion of the important algebra formulas involved, as well as a full solution to this particular problem, see:
http://magoosh.com/gmat/2013/three-alge ... -the-gmat/
[Reveal] Spoiler: OA

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Kudos [?]: 4 [0], given: 16

Re: In the diagram above, O is the center of the circle [#permalink] New post 01 May 2013, 10:13
Option A.

DC= a and DO =b
OC= DC-DO = b-a = radius of the circle.

From stmt 1:
(b-a)^2=36 or (b-a)=6 and area = 36pi. sufficient

From stmt 2:

we know a+b but we need to know the value of b-a. hence this is insufficient.
Re: In the diagram above, O is the center of the circle   [#permalink] 01 May 2013, 10:13
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In the diagram above, O is the center of the circle

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