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In the diagram above, the line y = 4 is the perpendicular bisector of

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In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink] New post 25 May 2011, 11:09
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Question Stats:

77% (02:04) correct 23% (01:53) wrong based on 40 sessions
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In the diagram above, the line y = 4 is the perpendicular bisector of segment JK (not shown). What is the distance from the origin to point K ?

A. 4
B. \(2\sqrt{10}\)
C. 8
D. \(6\sqrt{2}\)
E. \(4\sqrt{34}\)

[Reveal] Spoiler:
Attachment:
qimage040.gif
qimage040.gif [ 1.15 KiB | Viewed 278 times ]
[Reveal] Spoiler: OA

Last edited by Bunuel on 08 May 2015, 07:41, edited 1 time in total.
Renamed the topic, edited the question and added the OA.
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Re: In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink] New post 25 May 2011, 23:25
Refer to diagram:
Attachment:
SOLN.JPG
SOLN.JPG [ 13.1 KiB | Viewed 1767 times ]

y=4 is perpendicular bisector of JK
Hence distance between Point J and line y = 6 = distance between line y and point K.
Point K(6,-2)
Distance between point K and origin is 6^2+2^2= 2\sqrt{10}

OA B.

Please let me know the OA.
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Re: In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink] New post 25 May 2011, 23:40
coordinates of point k are (6,-2).
distance of J = 6 from y=4 means distance of 6 from y=4 for K gives y = -2.

thus 36+4 = distance from origin ^ 2
40 ^(1/2) = B
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Re: In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink] New post 03 Nov 2011, 12:15
Should be B. x^2= 2^2 + 6^2
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Re: In the diagram above, the line y = 4 is the perpendicular bisector of [#permalink] New post 08 May 2015, 07:41
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Re: In the diagram above, the line y = 4 is the perpendicular bisector of   [#permalink] 08 May 2015, 07:41
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In the diagram above, the line y = 4 is the perpendicular bisector of

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