Since we have the radius of the circle we can find out the length of the cord(AB).
Key: BC is the half of the radius.
AB = 2*sqrt(50^2-25^2)
AB = 2*cos30*50.
So, AB = 50sqrt(3)
let O as the center of the circle
then the area of triangle AOB = 50sqrt(3)*25*(1/2) = 1082.5
(1/3)*50^2*pi - 1082.5 = 15xx.xxxx
So, ans should be EEEEEEEEEEE
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