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In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
 01 Oct 2012, 05:07
Question Stats:
99% (01:23) correct
0% (00:00) wrong based on 3 sessions
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Projecty = kx + 3In the equation above, k is a constant. If y = 17 when x = 2, what is the value of y when x = 4 ? (A) 34 (B) 31 (C) 14 (D) 11 (E) 7 Practice Questions
Question: 54
Page: 159
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
01 Oct 2012, 05:17
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y = kx + 3 is the equation of the slope but in this context the question is different y = K * 2 + 3to have y = 17 then K must be 7 17 = 7*2 + 3y = 7*4 + 3 ---> y = 31B must be the answer. Sub 600 Thanks
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
04 Oct 2012, 02:47
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1) Put y =17 and x=2 and solve for K
2) Knowing k=7 from above and x=4 solve for Y ------> Y=31
Answer is B
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
01 Oct 2012, 05:08
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
01 Oct 2012, 19:53
Answer is B. Same explanation as Carcass's
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
04 Oct 2012, 00:43
Answer is B (=31)
Explanation is same as provided by Carcass above.
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
04 Oct 2012, 14:14
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
05 Oct 2012, 03:23
1 st step : solve given eqn for K by putting values of x and y. u get k=7
snd step : now put banck value of k=7 and x=4 in given eqn and solve for y.
you get y=31
so Y=31 answer
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Re: In the equation above, k is a constant. If y = 17 when x = 2 [#permalink]
10 Dec 2012, 04:47
y = kx + 3
17 = k(2) + 3 --> 14 = 2k --> k=7
y = (7)(4) + 3 --> y = 31
Answer: B
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Re: In the equation above, k is a constant. If y = 17 when x = 2
[#permalink]
10 Dec 2012, 04:47
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