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In the expression above, if xn#0, what is the value of S?

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In the expression above, if xn#0, what is the value of S? [#permalink] New post 18 Dec 2012, 08:13
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S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}

In the expression above, if xn#0, what is the value of S?

(1) x = 2n
(2) n = 1/2
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Re: In the expression above, if xn#0, what is the value of S? [#permalink] New post 18 Dec 2012, 08:17
S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}

In the expression above, if xn#0, what is the value of S?

S=\frac{\frac{2}{n}}{\frac{1}{x}+\frac{2}{3x}}=\frac{\frac{2}{n}}{\frac{5}{3x}}=\frac{6x}{5n}

(1) x = 2n --> S=\frac{6x}{5n}=\frac{6*2n}{5n}=\frac{12}{5}. Sufficient.

(2) n = 1/2. We need the value of x to answer the question. Not sufficient.

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Re: In the expression above, if xn#0, what is the value of S?   [#permalink] 18 Dec 2012, 08:17
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