in the figure : GMAT Problem Solving (PS)
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Senior Manager
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03 May 2011, 09:22
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Senior Manager
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Kudos [?]: 29 [0], given: 17

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03 May 2011, 13:02
You might want to repost in GMAT quant section, as this is the share your GMAT experience section... Might get more help that way...

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04 May 2011, 20:32
let the angle be x,

(x/360)* pi * 4^2 = 2 pi

x = 2 * 360 / 16 = 45

Thus C.
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04 May 2011, 22:37
amit2k9 wrote:
let the angle be x,

(x/360)* pi * 4^2 = 2 pi

x = 2 * 360 / 16 = 45

Thus C.

Either you are clairvoyant, or know what problem # this is... care to share what # out of what problem set it is?
VP
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Affiliations: PMI,QAI Global,eXampleCG
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04 May 2011, 22:42
humphy wrote:
amit2k9 wrote:
let the angle be x,

(x/360)* pi * 4^2 = 2 pi

x = 2 * 360 / 16 = 45

Thus C.

Either you are clairvoyant, or know what problem # this is... care to share what # out of what problem set it is?

I just used the whatever I know,

area of a sector = (unknown angle / 360 deg) * pi * (radius)^2
since radius is given and area of the shaded region is given as 2 * pi.

I substituted the values and got 45 deg.
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Re: in the figure   [#permalink] 04 May 2011, 22:42
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