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In the figure, AB = AE = 8, BC = CD = 13, and DE = 2. What

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In the figure, AB = AE = 8, BC = CD = 13, and DE = 2. What [#permalink] New post 14 Mar 2008, 23:51
In the figure, AB = AE = 8, BC = CD = 13, and DE = 2. What is the area of region
ABCDE ?
A. 76
B. 84
C. 92
D. 100
E. 108

see attached
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region abcde.jpg
region abcde.jpg [ 21.13 KiB | Viewed 949 times ]

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Re: Region ABCDE, SET29 Q10 [#permalink] New post 15 Mar 2008, 00:06
D.
Trapezoid (ABDE)=40 because: (DE+AB)/2 * AE
+
Triangle (BCD)=60, easiest way is to use HERON's formula. BC = CD = 13, BD=10 (Pythagorean theorem)
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Re: Region ABCDE, SET29 Q10 [#permalink] New post 15 Mar 2008, 01:29
Look at the figure and

The area of the figure is area of Rect (2*8) + area of Rt Angle Trngl( (1/2)* 8*6)+ area of Trngl CBD =100
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Geo.JPG
Geo.JPG [ 12.4 KiB | Viewed 933 times ]


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Re: Region ABCDE, SET29 Q10   [#permalink] 15 Mar 2008, 01:29
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In the figure, AB = AE = 8, BC = CD = 13, and DE = 2. What

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