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# In the figure above, D is a point on side AC of ?ABC.

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In the figure above, D is a point on side AC of ?ABC. [#permalink]  11 Apr 2005, 16:10
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18. In the figure above, D is a point on side AC of ΔABC. Is ΔABC is isosceles?
(1) The area of triangular region ABD is equal to the area of triangular region DBC.
(2) BD┴AC and AD = DC
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b too
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b is the OA... care to explain? I thought D
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B...
Trian ABD and Trian CBD are congruent triangles by the Side- angle-side theorem and hence AB is equal to BC

Angle ADC = Angle CDB --- Angle
Bd is the common side --- Side

Hope this helps
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Re: DS: geometry [#permalink]  13 Apr 2005, 02:30
ritledge wrote:
18. In the figure above, D is a point on side AC of ΔABC. Is ΔABC is isosceles?
(1) The area of triangular region ABD is equal to the area of triangular region DBC.
(2) BD┴AC and AD = DC

"B". but how come i can't see any figure above or my eyes are playing tricks on me
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I guess he has forgotten to post the figure ..... even i was
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swath20 wrote:
I guess he has forgotten to post the figure ..... even i was

I think both B suggests that the triangle can be issoceles or equilateral.

B is a theorem in an issoceles triangle whereas the same theorem is valid for equilateral triangle too.

The answer should be E ? Need some discussion on this one.
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