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In the figure above, D is a point on side AC of ?ABC.

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In the figure above, D is a point on side AC of ?ABC. [#permalink] New post 11 Apr 2005, 16:10
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18. In the figure above, D is a point on side AC of ΔABC. Is ΔABC is isosceles?
(1) The area of triangular region ABD is equal to the area of triangular region DBC.
(2) BD┴AC and AD = DC
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 [#permalink] New post 11 Apr 2005, 18:43
b too :wink:
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 [#permalink] New post 12 Apr 2005, 04:12
b is the OA... care to explain? I thought D
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 [#permalink] New post 12 Apr 2005, 17:14
B...
Trian ABD and Trian CBD are congruent triangles by the Side- angle-side theorem and hence AB is equal to BC

AD= CD --- side
Angle ADC = Angle CDB --- Angle
Bd is the common side --- Side

Hope this helps
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Re: DS: geometry [#permalink] New post 13 Apr 2005, 02:30
ritledge wrote:
18. In the figure above, D is a point on side AC of ΔABC. Is ΔABC is isosceles?
(1) The area of triangular region ABD is equal to the area of triangular region DBC.
(2) BD┴AC and AD = DC


"B". but how come i can't see any figure above or my eyes are playing tricks on me :roll:
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 [#permalink] New post 13 Apr 2005, 06:32
I guess he has forgotten to post the figure ..... even i was :roll:
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 [#permalink] New post 03 Jul 2006, 03:45
swath20 wrote:
I guess he has forgotten to post the figure ..... even i was :roll:


I think both B suggests that the triangle can be issoceles or equilateral.

B is a theorem in an issoceles triangle whereas the same theorem is valid for equilateral triangle too.

The answer should be E ? Need some discussion on this one.
  [#permalink] 03 Jul 2006, 03:45
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In the figure above, D is a point on side AC of ?ABC.

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