Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 18 May 2013, 14:54

# In the figure above, D is a point on side AC of ABC. Is ABC

Author Message
TAGS:
Manager
Joined: 31 Oct 2007
Posts: 117
Location: Frankfurt, Germany
Followers: 1

Kudos [?]: 20 [0], given: 0

In the figure above, D is a point on side AC of ABC. Is ABC [#permalink]  22 Mar 2008, 01:59
00:00

Question Stats:

0% (00:00) correct 100% (00:00) wrong based on 0 sessions
18. In the figure above, D is a point on side AC of ΔABC. Is ΔABC is isosceles?
(1) The area of triangular region ABD is equal to the area of triangular region DBC.
(2) BD┴AC and AD = DC
Attachments

triang ABCD.JPG [ 3.38 KiB | Viewed 477 times ]

_________________

Jimmy Low, Frankfurt, Germany
Blog: http://mytrainmaster.wordpress.com
GMAT Malaysia: http://gmatmalaysia.blogspot.com

Director
Joined: 10 Sep 2007
Posts: 958
Followers: 5

Kudos [?]: 151 [0], given: 0

Re: 1000DS: Section 2 Question 18 [#permalink]  22 Mar 2008, 07:02
Statement 1:
Tells us that Area of ABD is same as area of DBC. It might happen that AD is very small and DC is large thereby making AB longer and BC shorter. The reverse can also happen. As such this statement on its own in not sufficient.

Statement 2:
Tells us that AD = DC and BC is perpendicular on AC. This is good enough to tell us that AB = BC. You can also use triangle property to prove that AB = BC. (Two sides of triangles compared are equal).

Manager
Joined: 31 Oct 2007
Posts: 117
Location: Frankfurt, Germany
Followers: 1

Kudos [?]: 20 [0], given: 0

Re: 1000DS: Section 2 Question 18 [#permalink]  22 Mar 2008, 08:15
Yes, OA = B.

Do not quite understand your explanation for Statement 1. Mind elaborate?
_________________

Jimmy Low, Frankfurt, Germany
Blog: http://mytrainmaster.wordpress.com
GMAT Malaysia: http://gmatmalaysia.blogspot.com

Last edited by jimmylow on 22 Mar 2008, 08:16, edited 1 time in total.
Manager
Joined: 31 Oct 2007
Posts: 117
Location: Frankfurt, Germany
Followers: 1

Kudos [?]: 20 [0], given: 0

Re: 1000DS: Section 2 Question 18 [#permalink]  22 Mar 2008, 08:15
Yes, OA = B.

Do not quite understand your explanation for Statement 1. Mind elaborate?
_________________

Jimmy Low, Frankfurt, Germany
Blog: http://mytrainmaster.wordpress.com
GMAT Malaysia: http://gmatmalaysia.blogspot.com

Director
Joined: 10 Sep 2007
Posts: 958
Followers: 5

Kudos [?]: 151 [0], given: 0

Re: 1000DS: Section 2 Question 18 [#permalink]  22 Mar 2008, 09:19
ADB and BDC can have same area although AB and BC can be different. They do not have to be of same length. Height of both triangle is same. That means AD = DC. However as BD is can be at any angle rather than being perpendicular to AC, so value of AB and BC will vary and can be equal and cannot be equal. So this statement alone is not sufficient.
Re: 1000DS: Section 2 Question 18   [#permalink] 22 Mar 2008, 09:19
Similar topics Replies Last post
Similar
Topics:
In the figure above, D is a point on side AC of ?ABC. 6 11 Apr 2005, 17:10
D is a point on the side AC of a triangle ABC. Is ABC 9 17 Aug 2005, 12:05
In the figure above, D is a point on side AC of ?ABC. 3 14 Oct 2006, 09:37
1 D is a point on side AC of ABC. Is ABC is isosceles? (1) The 8 03 Jul 2010, 16:44
4 In the figure, point D divides side BC of triangle ABC into 9 01 Feb 2012, 16:32
Display posts from previous: Sort by