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# In the figure above, if PQRS is a parallelogram, then y - x

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In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  15 Oct 2012, 03:25
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Question Stats:

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Attachment:

PQRS.png [ 10.9 KiB | Viewed 7411 times ]
In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

Practice Questions
Question: 62
Page: 160
Difficulty: 650
[Reveal] Spoiler: OA

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Re: In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  15 Oct 2012, 03:25
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Expert's post

In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

In parallelogram corresponding angles are equal and consecutive angles are supplementary (supplementary angles are two angles that add up to 180°), thus:

$$140=2y$$ --> $$y=70$$;
$$2y+x=180$$ --> $$140+x=180$$ --> $$x=40$$;

Therefore, $$y-x=70-40=30$$.

For more check Polygons chapter of Math Book: math-polygons-87336.html
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Re: In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  15 Oct 2012, 03:34
2
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[quote="Bunuel"]The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Attachment:
PQRS.png
In the figure above, if PQRS is a parallelogram, then y - x =
(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

Note:- 1) Any two continuous interior angles of a parallelogram are supplementary.
2) Opposite angles are equal.

x= 180 - 140 = 40
x+2y = 180---> 2y = 180- x -----> 2y = 180- 40---->
y = 70

Thus y - x = 70 - 40 = 30
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Re: In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  15 Oct 2012, 10:08
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In the figure shown, angle x= QRS = QPS (opposite angles in parallelogram)
Also, intersecting lines PQ and PS, therefore QPS +Outerangle = 180
=> QPS =180-140 = 40
hence x =40

Also, Lines PQ and RS are parallel so angles they make with horizontal line PS are same. hence 2y =140
=> y =70

Therefore, y-x =70-40 = 30

Ans A.

Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Attachment:
PQRS.png
In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

Practice Questions
Question: 62
Page: 160
Difficulty: 650

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Re: In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  16 Oct 2012, 02:30
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since opposite sides and angles in a parallelogram are equal we know that

angle QRS = QPS = X
angle RSP = RPQ = 2y

140 + angle QPS = 180 ( sum of 2 angles on a straight line)

so X=40

now 2 ways to proceed sum of angles in parellogram is 360

so we have 2X+4Y=360
4Y = 360-80 ( 40*2)
4Y=280
Y=70 therefore Y-X=70-40 = 30 Answer Choice A

The other way since opposite sides are parallel PQ ll RS
hence 2Y=140 >>> y=70 and then Y-x = 70-40 = 30

In both cases Answer Choice is A
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Re: In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  19 Oct 2012, 03:21
Expert's post

In the figure above, if PQRS is a parallelogram, then y - x =

(A) 30
(B) 35
(C) 40
(D) 70
(E) 100

In parallelogram corresponding angles are equal and consecutive angles are supplementary (supplementary angles are two angles that add up to 180°), thus:

$$140=2y$$ --> $$y=70$$;
$$2y+x=180$$ --> $$140+x=180$$ --> $$x=40$$;

Therefore, $$y-x=70-40=30$$.

For more check Polygons chapter of Math Book: math-polygons-87336.html

Kudos points given to everyone with correct solution. Let me know if I missed someone.
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Re: In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  02 May 2013, 09:59
180-140= 40, x=40
140/2y= 70=y
y-x =
70-40=30
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Re: In the figure above, if PQRS is a parallelogram, then y - x [#permalink]  23 Dec 2014, 04:43
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Re: In the figure above, if PQRS is a parallelogram, then y - x   [#permalink] 23 Dec 2014, 04:43
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