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# In the figure above, if the raea of the triangle on the

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In the figure above, if the raea of the triangle on the [#permalink]

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12 Nov 2005, 21:51
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In the figure above, if the raea of the triangle on the right is twice the area of the triangle on the left, then in terms of s, S=

1. (sqrt(2)/2)*s
2. (sqrt(3)/2)*s
3. sqrt(2) * s
4. sqrt(3) * s
5. 2s

The figure shows 2 similar triangles with the exact same angles X, Y, and Z in the same places. The base of the smaller triangle is labeled s and the base of the larger one is labeled S

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12 Nov 2005, 22:51
12 Nov 2005, 22:51
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