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In the figure above, if z = 50, then x + y = [#permalink]
 27 Dec 2012, 07:09
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83% (01:52) correct
16% (00:15) wrong based on 7 sessions
Attachment: 
Angles.png [ 9.95 KiB | Viewed 589 times ]
In the figure above, if z = 50, then x + y = (A) 230 (B) 250 (C) 260 (D) 270 (E) 290
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Re: In the figure above, if z = 50, then x + y = [#permalink]
27 Dec 2012, 17:36
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Adding on to what Bunuel has explained,
Alternate angles between two parallel lines are equal, so angle Z is equal to Red angle = 50
Sum of all angles in a Triangle = 180 so , 90+50 (Red)+Blue = 180
Blue Angle = 40, hence X = 180-40 = 140 --> A
Sum of all interior angles in a Quadrilateral is 360,
So z+y+2 Right angles = 360
50+Y+90+90 = 360
Y = 360-230 = 130 --> B
From Statement A and Statement B we get x+y = 140+130 = 270
Ans D
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Re: In the figure above, if z = 50, then x + y = [#permalink]
27 Dec 2012, 07:19
 In the figure above, if z = 50, then x + y =(A) 230 (B) 250 (C) 260 (D) 270 (E) 290 Look at the diagram below: Attachment: 
Angles2.png [ 10.57 KiB | Viewed 525 times ]
Notice that red angles are equal, thus red angle in smaller triangle is 50 degrees as well: (red angle) = 40. Now, smaller triangle is right angled, thus (red angle) + (blue angle) = 90 --> 50 + (blue angle) = 90 --> (blue angle) = 40. Next, since x + (blue angle) = 180, then x = 140. Also, since (red angle) = 180 - y, then, y = 130. x + y = 140 + 130 = 270. Answer: D.
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Re: In the figure above, if z = 50, then x + y =
[#permalink]
27 Dec 2012, 07:19
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