Find all School-related info fast with the new School-Specific MBA Forum

It is currently 21 Sep 2014, 12:16

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In the figure above, JKLMN is a regular pentagon. Find the

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Expert Post
Magoosh GMAT Instructor
User avatar
Joined: 28 Dec 2011
Posts: 2093
Followers: 515

Kudos [?]: 2131 [0], given: 30

In the figure above, JKLMN is a regular pentagon. Find the [#permalink] New post 29 Oct 2013, 09:49
Expert's post
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

80% (02:02) correct 20% (00:59) wrong based on 40 sessions
Attachment:
pentagon.JPG
pentagon.JPG [ 19.74 KiB | Viewed 630 times ]

In the figure above, JKLMN is a regular pentagon. Find the measure of ∠JLK.
A. 24°
B. 36°
C. 48°
D. 60°
E. 72°

For more on polygons & regular polygons, as well as the solution to this problem, see:
http://magoosh.com/gmat/2012/polygons-a ... -the-gmat/

Mike :-)
[Reveal] Spoiler: OA

_________________

Mike McGarry
Magoosh Test Prep

Image

Image

Kaplan GMAT Prep Discount CodesKnewton GMAT Discount CodesGMAT Pill GMAT Discount Codes
Intern
Intern
avatar
Joined: 03 Oct 2013
Posts: 6
Followers: 0

Kudos [?]: 9 [0], given: 0

Re: In the figure above, JKLMN is a regular pentagon. Find the [#permalink] New post 29 Oct 2013, 13:06
Each interior angle of a regular polygon is given by 180*(n-2)/n, In this case this becomes 180*(5-2)/5=108
Therefore, <JKL = 108.
Since this is a regular pentagon, JK=KL and hence, <KJL = <KLJ = (180-108)/2 = 36
Re: In the figure above, JKLMN is a regular pentagon. Find the   [#permalink] 29 Oct 2013, 13:06
    Similar topics Author Replies Last post
Similar
Topics:
ABCDE is a regular pentagon with F at its center PrateekDua 0 27 Sep 2013, 08:46
A regular pentagon is inscribed in a circle. If A and B are pikachu 0 25 Dec 2012, 08:29
6 Experts publish their posts in the topic By sharing adjacent sides , exactly n regular pentagons can bhatiagp 13 22 Jun 2008, 04:13
8 Experts publish their posts in the topic A regular pentagon is inscribed in a circle. If A and B are bmwhype2 20 23 Oct 2007, 13:04
ABCDE is a regular pentagon with F at its center. How many shobhitb 1 11 Jun 2006, 00:24
Display posts from previous: Sort by

In the figure above, JKLMN is a regular pentagon. Find the

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.