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In the figure above, JKLMN is a regular pentagon. Find the

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Magoosh GMAT Instructor
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Kudos [?]: 3181 [0], given: 38

In the figure above, JKLMN is a regular pentagon. Find the [#permalink] New post 29 Oct 2013, 09:49
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Difficulty:

  35% (medium)

Question Stats:

77% (02:03) correct 23% (01:05) wrong based on 48 sessions
Attachment:
pentagon.JPG
pentagon.JPG [ 19.74 KiB | Viewed 968 times ]

In the figure above, JKLMN is a regular pentagon. Find the measure of ∠JLK.
A. 24°
B. 36°
C. 48°
D. 60°
E. 72°

For more on polygons & regular polygons, as well as the solution to this problem, see:
http://magoosh.com/gmat/2012/polygons-a ... -the-gmat/

Mike :-)
[Reveal] Spoiler: OA

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Mike McGarry
Magoosh Test Prep

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Kudos [?]: 10 [0], given: 0

Re: In the figure above, JKLMN is a regular pentagon. Find the [#permalink] New post 29 Oct 2013, 13:06
Each interior angle of a regular polygon is given by 180*(n-2)/n, In this case this becomes 180*(5-2)/5=108
Therefore, <JKL = 108.
Since this is a regular pentagon, JK=KL and hence, <KJL = <KLJ = (180-108)/2 = 36
Re: In the figure above, JKLMN is a regular pentagon. Find the   [#permalink] 29 Oct 2013, 13:06
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In the figure above, JKLMN is a regular pentagon. Find the

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