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In the figure above, the point on segment PQ that is twice a

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In the figure above, the point on segment PQ that is twice a [#permalink] New post 18 Sep 2012, 01:51
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Attachment:
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In the figure above, the point on segment PQ that is twice as far from P as from Q is

(A) (3,1)
(B) (2,1)
(C) (2,-1)
(D) (1.5,0.5)
(E) (1,0)

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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 18 Sep 2012, 01:52
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In the figure above, the point on segment PQ that is twice as far from P as from Q is

(A) (3,1)
(B) (2,1)
(C) (2,-1)
(D) (1.5,0.5)
(E) (1,0)

Options A or C cannot be correct answer since these points aren't even on segment PQ. E (1,0) is clearly closer to P, so it's also out, D is right in the middle of the segment, so only option B is left.

Answer: B.
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 18 Sep 2012, 02:19
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making a graph solving it we get (2,1)
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 18 Sep 2012, 05:30
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Bunuel wrote:

Attachment:
Plane.png
In the figure above, the point on segment PQ that is twice as far from P as from Q is

(A) (3,1)
(B) (2,1)
(C) (2,-1)
(D) (1.5,0.5)
(E) (1,0)



The question ask to divide the line PQ into 2:1 ratio and find the point.
By symmetry, the line segment at x-axis (1,0) will be divided in ratio 1:2.
Similarly, at (2,1) line will be divided in ration 2:1

Hence B
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 18 Sep 2012, 09:32
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Bunuel wrote:
The Official Guide for GMAT® Review, 13th Edition - Quantitative Questions Project

Attachment:
Plane.png
In the figure above, the point on segment PQ that is twice as far from P as from Q is

(A) (3,1)
(B) (2,1)
(C) (2,-1)
(D) (1.5,0.5)
(E) (1,0)

Practice Questions
Question: 43
Page: 158
Difficulty: 600


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By looking at the figure it comes out that option "B" (2,1) is the right choice.
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 21 Sep 2012, 02:18
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In the figure above, the point on segment PQ that is twice as far from P as from Q is

(A) (3,1)
(B) (2,1)
(C) (2,-1)
(D) (1.5,0.5)
(E) (1,0)

Options A or C cannot be correct answer since these points aren't even on segment PQ. E (1,0) is clearly closer to P, so it's also out, D is right in the middle of the segment, so only option B is left.

Answer: B.

Kudos points given to everyone with correct solution. Let me know if I missed someone.
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COLLECTION OF QUESTIONS:
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 26 Oct 2012, 02:25
twice as far from P as from Q

This confused me..I thought teh Qs is asking for the midpoint..

Could somebody explain me what it is asking..

and thanks bunuel for POE method. but how would u solve this algebraically?
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 21 Dec 2012, 14:14
Sachin9 wrote:
twice as far from P as from Q

This confused me..I thought teh Qs is asking for the midpoint..

Could somebody explain me what it is asking..

and thanks bunuel for POE method. but how would u solve this algebraically?



I concur. I think it would be helpful if we can solve this algebraically using the given y-coordinate and point Q, rather than elimination — similar to Bunel's approach to this problem.
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 22 Dec 2012, 00:49
Please suggest a algebraic approach, Bunuel!
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 22 Dec 2012, 04:04
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 26 Dec 2012, 02:06
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Lets see the algebraic solution.

A point P that divides a line AB internally into ratio m1 & m2 is as below.


A(x1,y1)____________m1_____________P(x3,y3)________________________m2__________________________B(x2,y2)

The formula for finding coordinates are as below.

x3 = (x1*m2 + x2*m1)/(m1 + m2)

y3 = (y1*m2 + y2*m1)/(m1 + m2)

Back to our question.

P (0,-1 ) & Q (3,2)

We fathom that m1 =2 & m2 = 1

x1 = 0 , y1 = -1

x2 = 3 , y1 = 2

Plugging values, we obtain answer as (2,1). Hence B

Once you know the formula its very easy.

P.S. Bunuel's approach is beautifully elegant. However, for me solving algebraically is much faster than figuring the answer choices out.
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 29 Dec 2012, 18:44
The only way to solve this problem is by plugging in answer choices?
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 30 Dec 2012, 00:11
fozzzy wrote:
The only way to solve this problem is by plugging in answer choices?


See this

in-the-figure-above-the-point-on-segment-pq-that-is-twice-a-139117.html#p1161061

If you need further elaboration, let me know.
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 30 Dec 2012, 01:10
I was thinking along those lines by forming a triangle and then solving it. This is a fairly easy question you can still use the answer choices but if its a bit more complicated I would like a fast approach.
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 30 Dec 2012, 01:26
fozzzy wrote:
I was thinking of using similar triangle property, I was thinking along those lines by forming a triangle and then solving it.


You can solve it easily using similar triangles too but you've picked the wrong triangles

Take the triangle with vertices [ (-1, 0) , (1,1) , (0,0) ]

and the triangle with vertices [ (3, 2) , (1,1) , (3,0) ]

These two triangles are similar since their lengths are in the ration 1:2

and then you can proceed.
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 19 Jan 2013, 03:24
eaakbari wrote:
Lets see the algebraic solution.

A point P that divides a line AB internally into ratio m1 & m2 is as below.


A(x1,y1)____________m1_____________P(x3,y3)________________________m2__________________________B(x2,y2)

The formula for finding coordinates are as below.

x3 = (x1*m2 + x2*m1)/(m1 + m2)

y3 = (y1*m2 + y2*m1)/(m1 + m2)

Back to our question.

P (0,-1 ) & Q (3,2)

We fathom that m1 =2 & m2 = 1

x1 = 0 , y1 = -1

x2 = 3 , y1 = 2

Plugging values, we obtain answer as (2,1). Hence B

Once you know the formula its very easy.

P.S. Bunuel's approach is beautifully elegant. However, for me solving algebraically is much faster than figuring the answer choices out.



This is called section formula. It will be helpful. Thanks
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 19 Jan 2013, 09:25
http://www.teacherschoice.com.au/Maths_ ... Geom_3.htm

go through the page..

ans is (2,1)
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 20 Jan 2013, 01:11
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I think with questions like these, the test writers are testing whether you'd quickly jump to using an algebraic approach, which in this case is much more time consuming, as compared to making the answer choices a part of your toolbox for finding the correct answer..
The question itself tells us we need to split the line into 3 equal parts with the asked coordinate being 2 parts away from P
A quick glance at the graph gives us the slope of 1, which easily shows us which points will cover the three segments
P(0,-1) --> (1,0) --> (2,1) --> Q(3,2)
Thus (2,1) being twice as far from P as from Q

True, an algebraic approach might be required for more complex problems where the slope isn't easily determined or the line segment might be split into a different ratio, but this question isn't testing that :)
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 06 Aug 2013, 00:41
Coordinates of point P = (0,-1)
Coordinates of point Q = (3,2)
Point required to be found is on segment PQ that is twice as far from P as from Q
So, adding (2,2) to point P (0,-1)
Answer = B = (2,1)
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Re: In the figure above, the point on segment PQ that is twice a [#permalink] New post 10 Aug 2014, 22:59
We can solve this question by applying distance formula also.

distance between two points

sqrt((x2-x1) +(y2-y1))^2

Here we take options one by one

P(0,-1) q(3,2)

when we take option (2,1)

we get distance sqrt(8) from point p sqrt (2) from point q.

so this point is twice as far as from point q.
Re: In the figure above, the point on segment PQ that is twice a   [#permalink] 10 Aug 2014, 22:59
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