In the figure above, triangle ABC is equilateral, and point

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In the figure above, triangle ABC is equilateral, and point [#permalink]

03 Dec 2012, 04:36

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Question Stats:

60% (01:32) correct

40% (00:38) wrong

based on 3 sessions

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ABC.png [ 4.92 KiB | Viewed 1020 times ]

In the figure above, triangle ABC is equilateral, and point P is equidistant from vertices A, B, and C. If triangle ABC is rotated clockwise about point P, what is the minimum number of degrees the triangle must be rotated so that point B will be in the position where point A is now?

(A) 60
(B) 120
(C) 180
(D) 240
(E) 270

[Reveal] Spoiler: OA

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Re: In the figure above, triangle ABC is equilateral, and point [#permalink]

03 Dec 2012, 04:40

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Walkabout wrote:

Attachment:

The attachment ABC.png is no longer available

Look at the diagram below:

Attachment:

ABC+.png [ 7.19 KiB | Viewed 1023 times ]

Each of the three red central angles is 120° (360/3=120). Thus in order point B to be in the position where point A is, the triangle should be rotated clockwise by 120°+120°=240°.

Answer: D.
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Re: In the figure above, triangle ABC is equilateral, and point [#permalink] 03 Dec 2012, 04:40

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In the figure above, triangle ABC is equilateral, and point

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In the figure above, triangle ABC is equilateral, and point

In the figure above, triangle ABC is equilateral, and point

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