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# In the figure above, two rectangles with the same dimentions

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In the figure above, two rectangles with the same dimentions [#permalink]  07 Jan 2008, 01:42
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In the figure above, two rectangles with the same dimentions overlap to form the shaded region. If each rectangle has perimeter 12 and the shaded region has perimeter 3, what is the total length of the heavy line segments?

a) 15
b) 18
c) 21
d) 22
e) 23

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2 Rectangles.doc [28 KiB]

Last edited by tarek99 on 07 Jan 2008, 05:14, edited 1 time in total.
Director
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Re: PS: Geometry [#permalink]  07 Jan 2008, 03:29
There is no solution for this question. Either you miss some data or I am so stupid I can not resolve it.
SVP
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Re: PS: Geometry [#permalink]  07 Jan 2008, 05:15
i'm really sorry! there was a typo in the question. i just corrected the question.
thanks! anyone?
Intern
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Re: PS: Geometry [#permalink]  07 Jan 2008, 13:42
Hi all, this is my first post..
I think the answer is C
Length of bold lines= 2*Perimeter of Rectangle - perimeter of shaded region
L=24-3
L=21

QA?
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Re: PS: Geometry [#permalink]  07 Jan 2008, 14:29
akhi wrote:
Hi all, this is my first post..
I think the answer is C
Length of bold lines= 2*Perimeter of Rectangle - perimeter of shaded region
L=24-3
L=21

QA?

yes. it is the length of the bolded lines in total. so it will be 24-3=21
C.

has been discussed earlier
SVP
Joined: 21 Jul 2006
Posts: 1551
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Re: PS: Geometry [#permalink]  12 Jan 2008, 11:33
damn, that was a lot easier than expected! thanks guys. the OA is C
Re: PS: Geometry   [#permalink] 12 Jan 2008, 11:33
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