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Re: In the figure above, what is the perimeter of rectangle ABPQ [#permalink]

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06 Oct 2003, 10:54

C?

My first would have been E, but then I saw AB was common in both rectangles, so I decided to answer C. But I decided to do a little calculation to verify. That took me like three-four minutes. Now seems like C is a good choice.

Re: In the figure above, what is the perimeter of rectangle ABPQ [#permalink]

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06 Oct 2003, 16:12

araspai wrote:

ABPQ is a smaller rectangle within a bigger rectangle ABCD, what is the peimeter of the rectangle ABPQ? a. The area of rectangular region ABCD is 3 times the area of the rectangular region ABPQ. b. The perimeter of bigger rectangle ABCD is 54.

A...clearly insufficient ..we only know A [ ABPQ] = 1/3 * A[ABCD]
3 * L * W1 = L * W
W = 3 W1
B... clearly insufficient
L + W = 27 ....

Re: In the figure above, what is the perimeter of rectangle ABPQ [#permalink]

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15 Jan 2016, 07:58

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Re: In the figure above, what is the perimeter of rectangle ABPQ [#permalink]

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20 Mar 2016, 06:25

I read in the Manhattan Geometry Guide (13 ed.) "If two similar triangles have corresponding side lengths in ratio a: b, then their areas will be in ratio a^2: b^2. The lengths being compared do not have to be sides— they can represent heights or perimeters. In fact, the figures do not have to be triangles."

So I guess, the parameters in this case should be in ratio as well. Can some one explain this to me.

I read in the Manhattan Geometry Guide (13 ed.) "If two similar triangles have corresponding side lengths in ratio a: b, then their areas will be in ratio a^2: b^2. The lengths being compared do not have to be sides— they can represent heights or perimeters. In fact, the figures do not have to be triangles."

So I guess, the parameters in this case should be in ratio as well. Can some one explain this to me.

Hi, you are correct -- If two polygons are similar, their corresponding sides, altitudes, medians, diagonals, angle bisectors and perimeters are all in the same ratio.

but here "You are not given anything about similarity", so you cannot apply the same rule here.. _________________

Re: In the figure above, what is the perimeter of rectangle ABPQ [#permalink]

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20 Mar 2016, 07:10

chetan2u wrote:

rickyfication wrote:

I read in the Manhattan Geometry Guide (13 ed.) "If two similar triangles have corresponding side lengths in ratio a: b, then their areas will be in ratio a^2: b^2. The lengths being compared do not have to be sides— they can represent heights or perimeters. In fact, the figures do not have to be triangles."

So I guess, the parameters in this case should be in ratio as well. Can some one explain this to me.

Hi, you are correct -- If two polygons are similar, their corresponding sides, altitudes, medians, diagonals, angle bisectors and perimeters are all in the same ratio.

but here "You are not given anything about similarity", so you cannot apply the same rule here..

Thanks, but I am finding it difficult to figure out why ABPQ and ABCD are not similar, since both the figures are rectangle, they have one common side therefore PQ has to be || with CD. is there anything wrong with my concept??

I read in the Manhattan Geometry Guide (13 ed.) "If two similar triangles have corresponding side lengths in ratio a: b, then their areas will be in ratio a^2: b^2. The lengths being compared do not have to be sides— they can represent heights or perimeters. In fact, the figures do not have to be triangles."

So I guess, the parameters in this case should be in ratio as well. Can some one explain this to me.

Hi, you are correct -- If two polygons are similar, their corresponding sides, altitudes, medians, diagonals, angle bisectors and perimeters are all in the same ratio.

but here "You are not given anything about similarity", so you cannot apply the same rule here..

Thanks, but I am finding it difficult to figure out why ABPQ and ABCD are not similar, since both the figures are rectangle, they have one common side therefore PQ has to be || with CD. is there anything wrong with my concept??

Hi, since you are also saying one side is equal and the other two side are lesser than their corresponding sides .. this basically means the sides are not in the same ratio.. whereas ONE set of sides have ratio as 1, the OTHER set is not 1, but something else.. for two triangles - ONE has L= 2 and B= 1, th eOTHER has L=6 and B=3.. these triangles are similar as ratios of sides 2/6 is same as 1/3 BUT if ONE has L= 2 and B= 1, th eOTHER has L=6 and B=1.. these triangles are NOT similar as ratios of sides 2/6 is NOT same as 1/1 _________________

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