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Re: In the figure above, what is the value of x? [#permalink]
02 May 2013, 00:32

3

This post received KUDOS

A little simpler way

Statement 1:

Angle BEC = z; As AE = EB = CD ==> we have Angle EBD = Angle ECD =x (Isosceles Triangle) z = 2x (exterior angle theorem) As BE = BC ==> z = x+y ==> 2x = x + y; means y =x

For Triangle ABC, Angle ACB + Angle CBA + Angle BAC = 180 (x+y) + (x+y) + x = 180 as x = y ==> x =y = 36 Statement 1 sufficient

Re: In the figure above, what is the value of x? [#permalink]
21 May 2013, 14:54

summer101 wrote:

A little simpler way

Statement 1:

Angle BEC = z; As AE = EB = CD ==> we have Angle EBD = Angle ECD =x (Isosceles Triangle) z = 2x (exterior angle theorem) As BE = BC ==> z = x+y ==> 2x = x + y; means y =x

For Triangle ABC, Angle ACB + Angle CBA + Angle BAC = 180 (x+y) + (x+y) + x = 180 as x = y ==> x =y = 36 Statement 1 sufficient

Statement 2: clearly insufficient

Ans A

Could you please elaborate on the highlighted one . As to , how did you arrive at Angle EBD = Angle ECD ??

Re: In the figure above, what is the value of x? [#permalink]
23 Sep 2014, 00:03

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