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In the figure attached, point O is the center of the circle [#permalink]
 16 Jan 2011, 16:56
Question Stats:
66% (03:31) correct
33% (01:33) wrong based on 1 sessions
In the figure attached, point O is the center of the circle and OC = AC = AB. What is the value of x (in degrees)? a. 40 b. 36 c. 34 d. 32 e. 30
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Advanced Triangles.png [ 36.77 KiB | Viewed 4282 times ]
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
16 Jan 2011, 19:07
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tonebeeze wrote: In the figure attached, point O is the center of the circle and OC = AC = AB. What is the value of x (in degrees)?
a. 40
b. 36
c. 34
d. 32
e. 30 It goes like this - In triangle OAB , Angle O + Angle A + Angle B = 180 -------1 OA = OB (Radius) => Angle A = Angle B In triangle ACB, Angle C = Angle O + Angle OAC (Sum of interior opposite angles) => Angle ACB = 2x; Also, AC = AB => Angle ACB = Angle ABC = 2x each Thus Angle A = Angle B = 2x each. So, substituting in 1 5x = 180 => x = 36 deg. This will help.
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
17 Jan 2011, 19:38
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Amazing question...kinda a very good revision of my triagnometry
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
18 Jan 2011, 20:51
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tonebeeze wrote: In the figure attached, point O is the center of the circle and OC = AC = AB. What is the value of x (in degrees)?
a. 40
b. 36
c. 34
d. 32
e. 30 A small diagram helps: Attachment: 
Ques1.jpg [ 9.23 KiB | Viewed 4163 times ]
In the figure, you see (180 - 2x) + y = 180 (straight angle) so 2x = y Also, the moment you see the circle and its two radii, mark them equal and the corresponding angles equal. (the red angle = blue angle) x + 180 - 2y = y 5x = 180 (from above, y = 2x) x = 36
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
19 Jan 2011, 22:38
Cool, but i think its an ez 600 question. isnt it?
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
19 Jan 2011, 23:57
in your original diagram OA and OB don't appear to be radii - the end points are off the circle... without getting them to be equal I dont think you can answer this question
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
20 Jan 2011, 00:03
I agree. i assumed that A and B are on the circle.
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
10 Mar 2011, 14:03
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Re: Quant Rev #161 Advanced Triangles Problem [#permalink]
11 Mar 2011, 01:14
tonebeeze wrote: In the figure attached, point O is the center of the circle and OC = AC = AB. What is the value of x (in degrees)?
a. 40
b. 36
c. 34
d. 32
e. 30 The figure attached is ambiguous. A needs to be shown on the circle, or at least it should be mentioned that A is also a point on the circle. If A is any point inside the circle, you cant solve this question from given information.
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Re: Quant Rev #161 Advanced Triangles Problem
[#permalink]
11 Mar 2011, 01:14
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