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# In the figure ( attachment), PQRS, initially in position I,

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Eternal Intern
Joined: 07 Jun 2003
Posts: 470
Location: Lone Star State
Followers: 1

Kudos [?]: 44 [0], given: 0

In the figure ( attachment), PQRS, initially in position I, [#permalink]  12 Jul 2003, 05:53
In the figure ( attachment), PQRS, initially in position I, has been rotated, clockwise about point S to position II. If P subscript two, Q subscript two, and R subscript two are the second positions of P, Q, and R, respectively, and if a side of the square is one, what is the length of the path followed by P in rotating to P subscript two?
SVP
Joined: 03 Feb 2003
Posts: 1608
Followers: 6

Kudos [?]: 76 [0], given: 0

I do not see a point S that is crucial for this question.
Assuming that S is a vertex of the right-bottom angle of the left square, the answer should be pi/2.

Correct?
Eternal Intern
Joined: 07 Jun 2003
Posts: 470
Location: Lone Star State
Followers: 1

Kudos [?]: 44 [0], given: 0

Stolyar [#permalink]  13 Jul 2003, 12:47
What time is it in Russia? So you work for financial services , an accountant? How did you know BB? You two sound incredibly talented. Your right, it is pi/ 2, but how?

All I know is the 1:1: sq root two formula.

VT
SVP
Joined: 03 Feb 2003
Posts: 1608
Followers: 6

Kudos [?]: 76 [0], given: 0

P moves clockwise by 90 degrees. Its radius SP is 1. So, you need to find a one fourth of a circumference with radius 1.

C=2pi*1
C/4=pi/2

P.S. The Moscow time is yours +8 hours. I am not an accountant; I work for an investment company that is active in a heavy industry. I am not that talented -- my score is 670. So, I have some space to get better

I plan to post my bio soon.
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