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Eternal Intern
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In the figure( attatchment), if PQRS is a square, PT is [#permalink]
 12 Jul 2003, 07:02
In the figure( attatchment), if PQRS is a square, PT is perpendicular to QT, QT=3, and PT=4, then RT=
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IMHO: RT = sqrt 58
correct?
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Eternal Intern
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How did you get it? [#permalink]
13 Jul 2003, 08:04
Can I see an artwork from you , how did you get it right?
SQ RT of 58 is correct 
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My rationale is to create a bigger square that embraces the given one. The points P, Q, R, and S touch the sides of the bigger square but not bisect them! They share each side of the bigger square by 4:3; this fact is clear from the information that PT is perpendicular to QT, QT=3, and PT=4.
Further, you have to see that the right vertical side of the bigger square is 7, and the bottom one is shared 4:3, maiking it possible to find RT via the right triangle (7-3-RT).
RT^2=7^2+3^2
RT=sqrt 58.
The trick is that a small square is inscribed into a bigger one, not bysecting the sides of the latter, but splitting them into a 4:3 proportion.
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Eternal Intern
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I agree with your logic, thanks!
How has Moscow grown over the years?
VT
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Moscow is enormous now. It is a different country if you compare it with other Russia. Moscow is one of the richest cities of the world, and one of the most expensive ones.
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