In the figure shown, the measure of angle PRS is how many degrees greater than the measure of angle PQR?
(1) The measure of angle QPR is 30 degrees
(2) The sume of the measures of angles PQR and PRQ is 150 degrees
Can someone show me how to solve this problem? the OA is D, but how? I chose E.
<S is 90 degree, hope this is correct
PQR + QPS = 90 ---(1)
RPS + PRS = 90 ---(2)
both are because of internal angles of triangle = 180, and S is 90
What we want to find is PRS - PQR
we equate (1) and (2)
PQR + QPS = RPS + PRS
Thus PRS - PQR = QPS - RPS
so if we know difference between QPS and RPS, then we know the answer
1) QPR = 30
QPR = QPS - RPS = 30 - sufficient
2) tells that QPR = 30 from internal angles of triangle, thus sufficient