Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

In the figure shown, the triangle is inscribed in the [#permalink]
25 Jan 2006, 09:29

00:00

A

B

C

D

E

Difficulty:

(N/A)

Question Stats:

50% (02:04) correct
50% (00:30) wrong based on 11 sessions

In the figure shown, the triangle is inscribed in the semicircle. If the length of line segment AB is 8 and the length of line segment BC is 6, what is the length of arc ABC?
A. 15 TT
B. 12 TT
C. 10 TT
D. 7 TT
E. 5 TT

Attachments

Untitled-1 copy.jpg [ 14.22 KiB | Viewed 5198 times ]

If a triangle is inscribed in a semi-circle, it will always be a right angle triangle with right angle at the corner which touches the arc portion of semi-circle (Like angle ABC here). _________________

If a triangle is inscribed in a semi-circle, it will always be a right angle triangle with right angle at the corner which touches the arc portion of semi-circle (Like angle ABC here).

Thank you for this. E is the answer. _________________

Angle in a semi circle is a right angle and ABC forms a right angle triangle with right angled at B.

so AB=8 AND BC=6 so AC=10 as 8-6-10 forms a right angled triangle with Hypotenuse AC

so Now we got the diameter =10 and radius =5

Now length of the Segment ABC=circumference/2 i.e 2*pi*r/2 as it is a semicircle so Now length of ABC=Pi*r and from above we know radius=5 so Lenght of segment ABC= 5*pi _________________