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In the first M games of a team's season, the ratio of the [#permalink]
21 May 2013, 07:10

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E

Difficulty:

45% (medium)

Question Stats:

54% (03:03) correct
46% (01:48) wrong based on 63 sessions

In the first M games of a team's season, the ratio of the team's wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team's wins to its losses for all M+N games?

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
21 May 2013, 07:19

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josemarioamaya wrote:

In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?

a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 37:77

The choice [E], I feel should be 31:77. **Request you to look into the source for the value.

As for the solution, if M is the games played in the first half, Total wins = M/3 Total Losses = 2*M/3

Similarly for N games, with the ratio 1:3 Total wins = N/4 Total Losses = 3N/4

Hence when combined, total games become M+N Total wins = M/3 + N/4 Total losses = 2M/3 + 3N/4

Now with the above, we know M:N = 4:5 i.e. M = 4N/5. Substituting the values, Total wins = 31N/60 Total losses = 77N/60

Hence the ratio is 31:77. Please correct me if I am wrong!

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
21 May 2013, 07:34

josemarioamaya wrote:

In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?

a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 37:77

Are you sure that the option E is 37:77. I'm getting 31:77. _________________

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
21 May 2013, 11:08

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Expert's post

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josemarioamaya wrote:

In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?

a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 31:77

As the final ratio is being asked, we can consider the value of M:N as 48:60.

First M(48) games, Wins = 16;Losses = 32

Succesive N(60) games, Wins = 15;Losses = 45

Total Wins:Total Losses = (16+15)/(32+45) = 31/77 E. _________________

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
21 May 2013, 11:10

vinaymimani wrote:

josemarioamaya wrote:

In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?

a) 7:18 b) 9:23 c) 11:27 d) 23:54 e) 31:77

As the final ratio is being asked, we can consider the value of M:N as 48:60.

First M(48) games, Wins = 16;Losses = 32

Succesive N(60) games, Wins = 15;Losses = 45

Total Wins:Total Losses = (16+15)/(32+45) = 31/77 E.

Why cant we consider 12:15 and end up with the ratio 9:23 which is option (B)

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
21 May 2013, 11:15

Expert's post

avinashrao9 wrote:

vinaymimani wrote:

josemarioamaya wrote:

In the first M games of a team´s season, the ratio of the team´s wins to its losses was 1:2. In the subsequent N games, the ratio of the team´s wins to losses was 1:3. If M:N = 4:5, what was the ratio of the team´s wins to its losses for all M+N games?

Why cant we consider 12:15 and end up with the ratio 9:23 which is option (B)

You will never got 9:23 for 12:15 .You will still get 31:77. _________________

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
21 May 2013, 11:23

I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
17 May 2014, 07:31

How about 12:20, its a perfect fit for 4:5 - M:N, an also all the other ratios.. and with this result I get 9:23.. really confused why this is the wrong answer..

Any help from the experts will be of great help!

avinashrao9 wrote:

I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
17 May 2014, 07:41

Expert's post

pkhats wrote:

How about 12:20, its a perfect fit for 4:5 - M:N, an also all the other ratios.. and with this result I get 9:23.. really confused why this is the wrong answer..

Any help from the experts will be of great help!

avinashrao9 wrote:

I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks

4:5 = 8:10 = 12:15 = 16:20 = ... but not 12:20. _________________

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
17 May 2014, 09:00

2

This post received KUDOS

pkhats wrote:

How about 12:20, its a perfect fit for 4:5 - M:N, an also all the other ratios.. and with this result I get 9:23.. really confused why this is the wrong answer..

Any help from the experts will be of great help!

avinashrao9 wrote:

I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks

12:20 is 3:5 and not 4:5 as required. We know that the ratio of in first M games in 1:2 which means, we have denominator as 3 if we want to find the numbers of wins and losses. In second case, the ratio of next N games is 1:3, making denominator 4.

Now M = 4x = 4 * 12x = 48 x (We are choosing 12 as it is LCM of 3 & 4) N = 5x = 5* 12x = 60 x Hence, we are taking the ratio as 48:60 and not any other ratio. Hope it helps!!!

Re: In the first M games of a team´s season, the ratio of the te [#permalink]
17 May 2014, 10:12

Oh!

Thanks both, Silly me! These silly mistakes are gonna make me cry one day - Hope not! :p

mittalg wrote:

pkhats wrote:

How about 12:20, its a perfect fit for 4:5 - M:N, an also all the other ratios.. and with this result I get 9:23.. really confused why this is the wrong answer..

Any help from the experts will be of great help!

avinashrao9 wrote:

I considered the ratio wrong.. Though 12:15 satisfies 4:5 condition, it does not work out for the number of matches mentioned. It has to be 48:60.. Thanks

12:20 is 3:5 and not 4:5 as required. We know that the ratio of in first M games in 1:2 which means, we have denominator as 3 if we want to find the numbers of wins and losses. In second case, the ratio of next N games is 1:3, making denominator 4.

Now M = 4x = 4 * 12x = 48 x (We are choosing 12 as it is LCM of 3 & 4) N = 5x = 5* 12x = 60 x Hence, we are taking the ratio as 48:60 and not any other ratio. Hope it helps!!!

_________________

GMAT- I'm gonna eat you whole ..!!

gmatclubot

Re: In the first M games of a team´s season, the ratio of the te
[#permalink]
17 May 2014, 10:12