Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: In the fraction [m][fraction]x/y[/fraction][/m] , where x an [#permalink]
27 Oct 2012, 22:06

5

This post received KUDOS

danzig wrote:

In the fraction \(\frac{x}{y}\) , where x and y are positive integers, what is the value of y ? (1) x is an even multiple of y. (2) x - y = 2

An alternative method rather than picking numbers?

1) Insufficient. We only get \(\frac{x}{y}=2a\). a can be any positive integer 2) Insufficient. x and y can be any two positive integers with a difference of 2 between them

Re: In the fraction [m][fraction]x/y[/fraction][/m] , where x an [#permalink]
29 Oct 2012, 03:59

1

This post received KUDOS

Expert's post

danzig wrote:

I don't understand why you assume that \(\frac{x}{y} = 2a\)

The statement indicates that x is an even multiple of y. So, there is the possibility that y is even. In that sense: \(\frac{x}{y} = a\) In other words, "the even part" of x is provided by y. So \(x = ay\), just that.

This fact could change the answer.

Please, your comments.

Correct: \(x=(2a)y\) if \(y\) is odd. But if \(y\) itself is even, then this won't necessarily be true. Consider \(x=y=2\).

In the fraction x/y, where x and y are positive integers, what is the value of y ?

(1) x is an even multiple of y --> \(x=even=my\), for some positive integer \(m\). Clearly insufficient: consider \(x=y=2\) and \(x=2\) and \(y=1\). Not sufficient.

(2) x - y = 2 --> \(x=y+2\). Not sufficient.

(1)+(2) Since from (1) \(x=my\), then from (2) \(y+2=my\) --> \(y=\frac{2}{m-1}\) --> \(m-1\) must be a factor of 2, thus it can be 1 (for \(m=2\)) or 2 (for \(m=3\)). But if \(m=3\), then \(y=1\) and \(x=3\), which is not even. Therefore, \(m=2\), \(y=2\) and \(x=4=even\). Sufficient.

Re: In the fraction x/y, where x and y are positive integers [#permalink]
29 Aug 2013, 08:30

1

This post received KUDOS

In the fraction x/y, where x and y are positive integers, what is the value of y ?

(1) x is an even multiple of y. (2) x - y = 2

Stmt 1: it says that x=y*even integer. So, if Y=2, X can be 0, 4, 8, 12, ... so on. But if Y=3, X can be 0, 6, 12, so on. So Y can be anything basically. Insufficient.

Stmt 2: Again, 5-3=2. Also 6-4=2. So Y can again be anything as long as X is 2 more than Y. Insufficient.

Together: We see that If Y=0 and X=2, Both statement 1 and 2 are satisfied but divisibility by 0 is not defined. So Y cannot be 0. If Y=1 and X=3, then 3-1=2 but 3 is not a even multiple of 1. If Y=2 and x=4, both conditions met. If Y=3, X will have to be 5, but again is not an even multiple of 3. Thinking of the patter here, if Y>2, then X will never produce x-y=2 when X is an even multiple of Y. Hence, y can only be 2. Satisfied.

Re: In the fraction [m][fraction]x/y[/fraction][/m] , where x an [#permalink]
28 Oct 2012, 12:10

I don't understand why you assume that \(\frac{x}{y} = 2a\)

The statement indicates that x is an even multiple of y. So, there is the possibility that y is even. In that sense: \(\frac{x}{y} = a\) In other words, "the even part" of x is provided by y. So \(x = ay\), just that.

Re: In the fraction [m][fraction]x/y[/fraction][/m] , where x an [#permalink]
29 Oct 2012, 05:32

Bunuel wrote:

danzig wrote:

I don't understand why you assume that \(\frac{x}{y} = 2a\)

The statement indicates that x is an even multiple of y. So, there is the possibility that y is even. In that sense: \(\frac{x}{y} = a\) In other words, "the even part" of x is provided by y. So \(x = ay\), just that.

This fact could change the answer.

Please, your comments.

Correct: \(x=(2a)y\) if \(y\) is odd. But if \(y\) itself is even, then this won't necessarily be true. Consider \(x=y=2\).

In the fraction x/y, where x and y are positive integers, what is the value of y ?

(1) x is an even multiple of y --> \(x=even=my\), for some positive integer \(m\). Clearly insufficient: consider \(x=y=2\) and \(x=2\) and \(y=1\). Not sufficient.

(2) x - y = 2 --> \(x=y+2\). Not sufficient.

(1)+(2) Since from (1) \(x=my\), then from (2) \(y+2=my\) --> \(y=\frac{2}{m-1}\) --> \(m-1\) must be a factor of 2, thus it can be 1 (for \(m=2\)) or 2 (for \(m=3\)). But if \(m=3\), then \(y=1\) and \(x=3\), which is not even. Therefore, \(m=2\), \(y=2\) and \(x=4=even\). Sufficient.

Answer: C.

Hope it's clear.

Since x was given as an even multiple,(i.e y times an even number would be x) I had taken \(\frac{x}{y}\) to be equal to 2a. If x were 2 and y were 2. Then x would not be an even multiple of y. Am I correct in my understanding of the term even multiple?? _________________

Did you find this post helpful?... Please let me know through the Kudos button.

Re: In the fraction [m][fraction]x/y[/fraction][/m] , where x an [#permalink]
29 Oct 2012, 05:35

Expert's post

MacFauz wrote:

Bunuel wrote:

danzig wrote:

I don't understand why you assume that \(\frac{x}{y} = 2a\)

The statement indicates that x is an even multiple of y. So, there is the possibility that y is even. In that sense: \(\frac{x}{y} = a\) In other words, "the even part" of x is provided by y. So \(x = ay\), just that.

This fact could change the answer.

Please, your comments.

Correct: \(x=(2a)y\) if \(y\) is odd. But if \(y\) itself is even, then this won't necessarily be true. Consider \(x=y=2\).

In the fraction x/y, where x and y are positive integers, what is the value of y ?

(1) x is an even multiple of y --> \(x=even=my\), for some positive integer \(m\). Clearly insufficient: consider \(x=y=2\) and \(x=2\) and \(y=1\). Not sufficient.

(2) x - y = 2 --> \(x=y+2\). Not sufficient.

(1)+(2) Since from (1) \(x=my\), then from (2) \(y+2=my\) --> \(y=\frac{2}{m-1}\) --> \(m-1\) must be a factor of 2, thus it can be 1 (for \(m=2\)) or 2 (for \(m=3\)). But if \(m=3\), then \(y=1\) and \(x=3\), which is not even. Therefore, \(m=2\), \(y=2\) and \(x=4=even\). Sufficient.

Answer: C.

Hope it's clear.

Since x was given as an even multiple,(i.e y times an even number would be x) I had taken \(\frac{x}{y}\) to be equal to 2a. If x were 2 and y were 2. Then x would not be an even multiple of y. Am I correct in my understanding of the term even multiple??

x is an even multiple of y means that x is even AND a multiple of y. _________________

Re: In the fraction x/y, where x and y are positive integers [#permalink]
14 Oct 2014, 20:38

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

How the growth of emerging markets will strain global finance : Emerging economies need access to capital (i.e., finance) in order to fund the projects necessary for...

One question I get a lot from prospective students is what to do in the summer before the MBA program. Like a lot of folks from non traditional backgrounds...