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In the fraction x/y, where x and y are positive integers,

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Director
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In the fraction x/y, where x and y are positive integers, [#permalink] New post 05 Oct 2006, 00:23
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E

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In the fraction x/y, where x and y are positive integers, what is the value of Y?

1> The least common denominator of x/y and 1/3 is 6.
2> x = 1

Please explain for everyone's benefit.
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 [#permalink] New post 05 Oct 2006, 00:59
E for me.

from 1. y can be 2 or 6.
1 and 2 together, y still can be 2 or 6.
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 [#permalink] New post 05 Oct 2006, 01:12
tennis_ball wrote:
E for me.

from 1. y can be 2 or 6.
1 and 2 together, y still can be 2 or 6.


Look at the bold part . how can this be true?

For x=1 and y=6

The given expression becomes 1/6+1/3 = 3/6 = 1/2.
So the least denominator is 2 and not 6.

So x=1 and y=2 is the only possible solution

ie 1/2 +1/3 = 1/6.

Is there any mistake with this?
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 [#permalink] New post 05 Oct 2006, 01:35
According to wikipedia:

In mathematics, the lowest common denominator or least common denominator (abbreviated LCD) is the least common multiple of the denominators of a set of vulgar fractions.


It is the smallest (non-zero) number that is a multiple of the denominators. For instance, the LCD of \left\{ \frac{1}{2}, \frac{1}{4} \right\} is 4 because the least common multiple of 2 and 4 is 4. Likewise the LCD of \left\{ \frac{1}{2}, \frac{1}{3} \right\} is 6.
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 [#permalink] New post 05 Oct 2006, 01:50
Hey tennisball, i neglected the statement least common denominator.

Thank you...

So it is E
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 [#permalink] New post 05 Oct 2006, 09:49
In the fraction x/y, where x and y are positive integers, what is the value of Y?

1> The least common denominator of x/y and 1/3 is 6.
2> x = 1

1) LCM = 6 so y has to be 6. SUFF.

2)Unsufficient

A.
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 [#permalink] New post 05 Oct 2006, 10:55
In the fraction x/y, where x and y are positive integers, what is the value of Y?

1> The least common denominator of x/y and 1/3 is 6.
2> x = 1

from one

y could be 2 or 6......insuff

from two

we have no info about y...insuff

both

still y could be 2 or 6 my answer is e
  [#permalink] 05 Oct 2006, 10:55
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In the fraction x/y, where x and y are positive integers,

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