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Manager
Status: Never ever give up on youself.Period.
Joined: 23 Aug 2012
Posts: 133
Location: India
Concentration: Finance, Human Resources
GMAT 1: 570 Q47 V21
GMAT 2: 690 Q50 V33
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[0], given: 31
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In the list above, k, m, and n are three distinct positive i [#permalink]
 14 Jan 2013, 06:25
Question Stats:
60% (03:42) correct
40% (02:07) wrong based on 0 sessions
3, k, 20, m, 4, n In the list above, k, m, and n are three distinct positive integers and the average (arithmetic mean) of the six numbers in the list is 8. If the median of the list is 6.5, which of the following CANNOT be the value of k, m, or n ? A.9 B.8 C.7 D.6 E.5 I didn't get the answer.My answer came out to be A.9..Help!!!!!!
_________________
Don't give up on yourself ever. Period.
Beat it, no one wants to be defeated (My journey from 570 to 690) : beat-it-no-one-wants-to-be-defeated-journey-570-to-149968.html
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Intern
Joined: 27 Dec 2012
Posts: 9
Location: India
Concentration: Technology, General Management
GMAT Date: 06-27-2013
GPA: 3
WE: Engineering (Energy and Utilities)
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13
[1] , given: 1
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Re: In the list above, k, m, and n are three distinct positive i [#permalink]
14 Jan 2013, 13:15
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sum of all numbers = 8*6=48
and so k+m+n =21----------- (1)
in this list it can be safely assumed that 20 is the biggest number, because even if we assume 21 to be one of the nos, it would not satisfy the sum =48 condition.
median is (sum of middle two terms)/2, if no of terms is even.
So 3rd term + 4th term = 13 ---(2)
So we have to arrange the six number in increasing order. both 3 and 4 cannot be 3rd and 4th terms so that means, there is at max one term which is less than 3. So then there are two cases:
1st case. let us assume that k is less than 3: the order is k,3,4,m,n,20
4+m=13 from (2)
m=9
so from--(1) k+n=12
which means out of the five options 9 is already in.
But since k is less than 3, the values of n would be either 11 or 12 (not in options)
2nd Case: if k is greater than 4
3,4,k,m,n,20
in this case k+m=13 and hence n = 8
now k is greater than 4, if k =5 then m=8 which cant be because already n=8 and as per question all k, m and n are distinct integers.
hence 5 cant be the choice.
DJ
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Manager
Status: Never ever give up on youself.Period.
Joined: 23 Aug 2012
Posts: 133
Location: India
Concentration: Finance, Human Resources
GMAT 1: 570 Q47 V21
GMAT 2: 690 Q50 V33
GPA: 3.5
WE: Information Technology (Investment Banking)
Followers: 5
Kudos [?]:
38
[0], given: 31
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Re: In the list above, k, m, and n are three distinct positive i [#permalink]
14 Jan 2013, 18:48
DISTINCT...I missed this word...so i eliminated choice E,as I got the values 3-4-5-8-8-20 ,which had median as 6.5...thnks for the explaination...+1 Posted from my mobile device 
_________________
Don't give up on yourself ever. Period.
Beat it, no one wants to be defeated (My journey from 570 to 690) : beat-it-no-one-wants-to-be-defeated-journey-570-to-149968.html
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Re: In the list above, k, m, and n are three distinct positive i
[#permalink]
14 Jan 2013, 18:48
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