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# In the pizza palace, 95% of the customers order pizza. if

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In the pizza palace, 95% of the customers order pizza. if [#permalink]  09 Oct 2003, 21:57
In the pizza palace, 95% of the customers order pizza. if 65% of the customers who order pizza also eat breadsticks, find the probability that a customer who ordrs a pizza willl order breadsticks.
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[#permalink]  13 Oct 2003, 10:02
I vote for 0.95*0.65=0.6175
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[#permalink]  13 Oct 2003, 12:40
Me too. 0.6175

65% of 95% = 61.75%
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[#permalink]  16 Oct 2003, 00:24
praet was right, ans 13/19 (about 68%)
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[#permalink]  19 Oct 2003, 15:46
IMHO, there must be a mistake in the problem statement. Because for the answer 13/19 to be true, the problem statement should be like this:

In the pizza palace, 95% of the customers order pizza. If the 65% of the customer order both pizza and breadsticks( instead of if 65% of the customers who order pizza also eat breadsticks), find the probability that a customer who ordrs a pizza willl order breadsticks.

Please see the attachement for the explanation.

Friends, please let me know if my explanation sounds reasonable to you.

p.s. If we consider the problem statement as it is, stolyar's and amarsesh's response would indicate "probability of ANY CUSTOMER ordering breadsticks".
Attachments

probability22.doc [27.5 KiB]

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[#permalink]  19 Oct 2003, 18:42
am1974 wrote:
IMHO, there must be a mistake in the problem statement. Because for the answer 13/19 to be true, the problem statement should be like this:

In the pizza palace, 95% of the customers order pizza. If the 65% of the customer order both pizza and breadsticks( instead of if 65% of the customers who order pizza also eat breadsticks), find the probability that a customer who ordrs a pizza willl order breadsticks.

Please see the attachement for the explanation.

Friends, please let me know if my explanation sounds reasonable to you.

p.s. If we consider the problem statement as it is, stolyar's and amarsesh's response would indicate "probability of ANY CUSTOMER ordering breadsticks".

I think you are correct. If 65% of the customers who order pizza order breakstick, then the probability that a customer who orders a pizza will order breadsticks is simply 65%.
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AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

[#permalink] 19 Oct 2003, 18:42
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