Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 06 May 2015, 21:10

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In the rectangular coordinate system, are the points (r,s)

 Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

In the rectangular coordinate system, are the points (r,s) [#permalink]  21 Feb 2006, 07:31
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:34) correct 0% (00:00) wrong based on 8 sessions
In the rectangular coordinate system, are the points (r,s) and (u,v) equidistant from the origin?

1) r+s = 1

2) u = 1 - r, v = 1 - s
Senior Manager
Joined: 11 Jan 2006
Posts: 270
Location: Chennai,India
Followers: 1

Kudos [?]: 3 [0], given: 0

[#permalink]  21 Feb 2006, 07:35
it is B ,

1) we only know the value of r & s - insuffi

2) we know the value of u & s and can calculate r & s , since the distance from origin is asked - the calculation is simple.. - suffi
_________________

vazlkaiye porkalam vazltuthan parkanum.... porkalam maralam porkalthan maruma

Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

[#permalink]  21 Feb 2006, 07:46
That's what I got but GMATPrep says c)??????
Intern
Joined: 13 Nov 2005
Posts: 9
Followers: 0

Kudos [?]: 0 [0], given: 0

[#permalink]  21 Feb 2006, 08:03
I think it is C.

The reason is :
With either assumption we cannot get an answer. Both have to be taken together to get the values we require.

Way2go
Manager
Joined: 13 Dec 2005
Posts: 224
Location: Milwaukee,WI
Followers: 1

Kudos [?]: 7 [0], given: 0

[#permalink]  21 Feb 2006, 08:41
The question here is r they equidistant or Not ... so the answer has to be YES OR NO .....

this u can only find by taking both A & B together .

by taking both the equation together u will get

u =s and v =r so the two coordinates turns out to be (r,s) and (s,r)

so both of them are equidistant from the origin.
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

[#permalink]  21 Feb 2006, 12:44
But will 2) not give us the information we need since for any value of r,s we know the corresponding value of u,v?
Manager
Joined: 13 Dec 2005
Posts: 224
Location: Milwaukee,WI
Followers: 1

Kudos [?]: 7 [0], given: 0

[#permalink]  21 Feb 2006, 13:22

going by what u said ... like choosing the option 2 and knowing the values of parameter u can findout whether its equidistant or not ... well here u dont know the values so if i ask u whether its equidistant or not u cant make out yes or no .

for example in take value r =1/2 ,s =1/2 so u =1/2 and v =1/2 ... means they are the same point and hence equidistant , now u put

r =2 ,s =2 so u =-1 and v = -1 so not equidistant ... so u really cannot
generalise from it what the answer will be ..definite yes or definite no

but when u take both 1 and 2 u get that irrespective of the value of the parameters, they are equi distant . Hence C .
Senior Manager
Joined: 20 Feb 2006
Posts: 373
Followers: 1

Kudos [?]: 2 [0], given: 0

[#permalink]  21 Feb 2006, 14:39
Thanks IPC,

I see what you're saying.
Intern
Joined: 31 May 2005
Posts: 12
Followers: 0

Kudos [?]: 0 [0], given: 0

[#permalink]  28 Feb 2006, 18:54
C

sqrt (r^2 +s^2) - sqrt (u^2+v^2) = sqrt ((1-r)^2 = (1-s)^2))

solving this by substituting given in 1) we arrive at C.
SVP
Joined: 14 Dec 2004
Posts: 1707
Followers: 1

Kudos [?]: 51 [0], given: 0

[#permalink]  01 Mar 2006, 10:49
This is "C".

we get
v^2+u^2 = r^2 + s^2 + 2 - 2(r+s)

Putting r+s = 1, we get, v^2+u^2 = r^2 + s^2
Intern
Joined: 17 Feb 2006
Posts: 11
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: Rectangular coordinate DS [#permalink]  01 Mar 2006, 11:08
In the rectangular coordinate system, are the points (r,s) and (u,v) equidistant from the origin?

1) r+s = 1

2) u = 1 - r, v = 1 - s

The answer is C.

1) gives us r+s but no information on u or v --> insufficient

2) gives us the distance from the origin as follows:

root [(1-r)^2 + (1-s)^2] = root [1 -2r + r^2 + 1 -2s + s^2]

= root [r^2 + s^2 + 2 - 2(r+s)]

From here we cannot tell whether the points are equidistant or not - it depends on whether the expression 2-2(r+s) = 0

Taking both (1) and (2) into account 2-2(r+s) = 2-2*1 = 0 --> sufficient

Re: Rectangular coordinate DS   [#permalink] 01 Mar 2006, 11:08
Similar topics Replies Last post
Similar
Topics:
In the rectangular coordinate system, are the points (r,s) 4 27 Aug 2007, 08:02
In the rectangular coordinate system, are the points (r,s) 4 03 Aug 2007, 18:48
In the rectangular co-ordinate systems, are the points (r,s) 2 22 Jul 2006, 15:00
In the rectangular coordinate system, are the points (r,s) 6 15 Jun 2006, 00:12
In the rectangular coordinate system, are the points (r,s) 3 04 Jan 2006, 18:00
Display posts from previous: Sort by

# In the rectangular coordinate system, are the points (r,s)

 Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.