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In the rectangular coordinate system, if the line x = 2y + 5

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In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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27 May 2012, 09:05
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In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?

A. -2
B. 0
C. 1/2
D. 1
E. 2
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Re: In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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27 May 2012, 09:19
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macjas wrote:
In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?

A. -2
B. 0
C. 1/2
D. 1
E. 2

The line x = 2y + 5 passes through points (m,n) and (m + 2,n + p) means that m=2n+5 and m+2=2(n+p)+5. Now, subtract the first equation from the second: (m+2)-m=2(n+p)+5-(2n+5) --> 2=2p --> p=1.

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Re: In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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29 May 2012, 07:46
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Another way: Slope of the line can be calculated...

y=mx+c => y= (1/2)x-5/2 => 1/2=n+p-n/m+2-m =>1/2=p/2 => p=1
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Re: In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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12 Oct 2013, 17:19
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Re: In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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18 Mar 2015, 17:37
Hello from the GMAT Club BumpBot!

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Re: In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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18 Mar 2015, 20:23
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Expert's post
Hi All,

When dealing with a graphing question, it often helps to convert any equations you've been given into "slope-intercept" format (and you might find it helpful to physically draw the graph so you can see it).

Here, we're given the line X = 2Y = 5. Converting that into slope-intercept gives us:

2Y = X - 5

Y = X/2 - 5/2

We're then told that the line passes through the points (M,N) and (M+2,N+P). We're asked for the value of P.

Since we have the line, we can TEST a set of co-ordinate for (M,N)

IF.....
X = 0
Y = -5/2

So (M,N) is the point (0, -5/2)

The second point is (M+2,N+P)

Since our M = 0......M+2 = 2..... we have to see what happens when....

X = 2
Y = 1 - 5/2 = -3/2

So (M+2,N+P) is the point (2, -3/2)

So between the first point and the second point, what has happened to the Y co-ordinate? It went from -5/2 to -3/2, so it INCREASED by 1.

Thus, P = 1

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Re: In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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16 Jun 2015, 12:35
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macjas wrote:
In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?

A. -2
B. 0
C. 1/2
D. 1
E. 2

Rewrite x = 2y + 5 like so: y = 0.5X + 2.5

Plug in Values for m = x:

if m = x = 1, the first point is 1, 3
if m = x = 3, the second point is 3, 4

Therefore n = 3 and n + p = 4. p = 1
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Re: In the rectangular coordinate system, if the line x = 2y + 5 [#permalink]

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14 Jul 2016, 04:15
macjas wrote:
In the rectangular coordinate system, if the line x = 2y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p ?

A. -2
B. 0
C. 1/2
D. 1
E. 2

If 2y+5=x
then, 2y=x-5
or $$y=\frac{x}{2}-\frac{5}{2}$$

Now this has become the equation of line in the point slope form. {y=mx+b}
slope (m) is 1/2
and we also know Slope (m)=$$\frac{y2-y1}{x2-x1}$$

threfore putting the value of x and y from the question we get
$$\frac{n+p-n}{m+2-m} = \frac{1}{2}$$

$$\frac{p}{2}=\frac{1}{2}$$ ===> p=1

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Re: In the rectangular coordinate system, if the line x = 2y + 5   [#permalink] 14 Jul 2016, 04:15
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