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In the sequence 1, 2, 4, 8, 16, 32, , each term after the

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In the sequence 1, 2, 4, 8, 16, 32, , each term after the [#permalink] New post 25 Apr 2006, 11:34
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A
B
C
D
E

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In the sequence 1, 2, 4, 8, 16, 32, …, each term after the first is twice the previous term. What is the sum of the 16th, 17th, and 18th terms in the sequence?

A. 2^18
B. 3(2^17)
C. 7(2^16)
D. 3(2^16)
E. 7(2^15)
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 [#permalink] New post 25 Apr 2006, 12:27
This series can be written as
1, 2^1,2^2,2^3...
So the nth term = 2^n-1

So the sum of 16,17,18 th term = 2^15 +2^16 + 2^17
= 2^15(1+2+4) Answer = E
  [#permalink] 25 Apr 2006, 12:27
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In the sequence 1, 2, 4, 8, 16, 32, , each term after the

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