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# In the sequence above, each term after the first 1/2 of the preceding

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Manager
Joined: 09 Jun 2010
Posts: 78
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Kudos [?]: 19 [1] , given: 17

In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Jul 2010, 22:37
1
KUDOS
00:00

Difficulty:

25% (medium)

Question Stats:

75% (01:51) correct 25% (00:00) wrong based on 12 sessions

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240,120,60,30

In the sequence above, each term after the first 1/2 of the preceding term. What is the least term of the sequence is greater than 1 ?

A. 32/15
B. 16/15
C. 15/8
D. 15/4
E. 15/2
[Reveal] Spoiler: OA
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Kudos [?]: 93108 [0], given: 10552

Re: In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Jul 2010, 22:57
xmagedo wrote:
240,120,60,30

In the sequnce above, each term after the first 1/2 of the preceding term. What is the least term of the sequnce is greater than 1 ?

a 32/15
b 16/15
c 15/8
d 15/4
e 15/2

pleas help with a formula

There is no need for formula:
240, 120, 60, 30, 30/2, 30/4, 30/8, 30/16, 30/32<1. So the leas term more than 1 is 30/16=15/8.

But still if you need: $$\frac{30}{2^n}>1$$, where n is integer --> $$2^n<30$$ --> $$n<5$$ --> $$n=4$$ --> $$\frac{30}{2^n}=\frac{30}{2^4}=\frac{15}{8}$$.

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Kudos [?]: 163 [0], given: 0

Re: In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Nov 2016, 06:36
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Kudos [?]: 633 [0], given: 317

Re: In the sequence above, each term after the first 1/2 of the preceding [#permalink]

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29 Nov 2016, 08:19
xmagedo wrote:
240,120,60,30

In the sequence above, each term after the first 1/2 of the preceding term. What is the least term of the sequence is greater than 1 ?

A. 32/15
B. 16/15
C. 15/8
D. 15/4
E. 15/2

Greater than 1 = Numerator > Denominator

Now, go fearlessly- 30, 15 , 15/2 , 15/4 , 15/8, 15/16

Hence, the answer can be found in 10 seconds and it is (C)

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Re: In the sequence above, each term after the first 1/2 of the preceding   [#permalink] 29 Nov 2016, 08:19
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