Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

This is a tough 'un. First of all I'm guessing the sum is abcd, not cbcd as you wrote.

(1) b<c, Since the sums that lead to b and c are identical (y+v in the tens place and v+y in the hundreds place), the only way that this can happen is if the sum in the units place (v+z) is at least 10, and y+v is less than 10. This means that v+z = v+ (v+3) = 2v+3 > 10. Also we know that v+y = v+(v-3)=2v-3 < 10. This doesn't tell us what v is, only that v is between 4 and 6. Not suff.

(2) z>7, since z=v+3 this means that v>4. Again not suff.

Taking them together all we know is that v is either 5 or 6. But there is no way to know exactly what is a=v+3.

I think answer is D. From the information given we have: d=2v+3 c= 2v-3 b= 2v-3 c=3+v = z 1) b<c => 2v-3<3+v => v<6 We know that c#b, unless z+v>10. From this b+1=c. From this v>3. So the only possible values of v are 4 and 5. For v=4 is impossible, so v=5 - suff 2) z>7 => c>7 => 3+v>7 => v>4. So v could have possible values 5,6,7,8,9. For every v>=6 the result will have 5 digits. So v=5.

This week went in reviewing all the topics that I have covered in my previous study session. I reviewed all the notes that I have made and started reviewing the Quant...

I was checking my phone all day. I wasn’t sure when I would receive the admission decision from Tepper. I received an acceptance from Goizueta in the early morning...

I started running as a cross country team member since highshcool and what’s really awesome about running is that...you never get bored of it! I participated in...