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In the table above is shown the percent reduction in the

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In the table above is shown the percent reduction in the [#permalink] New post 23 Jul 2011, 20:12
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Question Stats:

29% (02:24) correct 71% (01:52) wrong based on 127 sessions
Date of Purchase
Percent Reduction

July 1 through July 7
5%

July 8 through July 14
30%

July 15 through July 21
55%

July 22 through July 28
70%

In the table above is shown the percent reduction in the price of every item in a store off the original price of that item on June 30 of that year. The table is for the 28 days immediately after June 30 of that year. If on July n of that year, Bill bought a suit that originally cost $450, what is the value of n?

(1) Bill paid $112.50 less than he would have if he had bought it the day before.

(2) Bill paid $202.50 for the suit.
[Reveal] Spoiler: OA
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Re: DS - 700 level - Suit [#permalink] New post 23 Jul 2011, 20:27
interesting question..

i think i will choose A for this... only statement 1 is sufficient...

how i solved?
B - of course is sufficient.. $202.50 .. falls under 3rd category BUT i dont know which day in 3rd category.. it can be any from july 15th through 21st...

now for A to be correct there is hint... to see if 55% of 450 - 30% of 450 = 112.50 and i think it is.
so it is the 15th day of july
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Re: DS - 700 level - Suit [#permalink] New post 23 Jul 2011, 20:40
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bschool83 wrote:
Date of Purchase
Percent Reduction

July 1 through July 7
5%

July 8 through July 14
30%

July 15 through July 21
55%

July 22 through July 28
70%


In the table above is shown the percent reduction in the price of every item in a store off the original price of that item on June 30 of that year. The table is for the 28 days immediately after June 30 of that year. If on July n of that year, Bill bought a suit that originally cost $450, what is the value of n?

(1) Bill paid $112.50 less than he would have if he had bought it the day before.

(2) Bill paid $202.50 for the suit.


Can't do much about it except solving:
1)
450*0.95=427.5
450*0.7=315
450*0.45=202.5
450*0.3=135.0

427.5-315=112.5 => n=8
315-202.5=112.5 => n=15
Not Sufficient.

2)

15<=n<=21
Not Sufficient.

Together:
n=15

Ans: "C"
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Re: DS - 700 level - Suit [#permalink] New post 23 Jul 2011, 20:49
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Fluke is right. This is a typical DS trap. If we see that a difference of 112.50 show up at the junction of two date ranges, we figure we have the answer and start congratulating ourselves. However, it's really important to check and see if there is more than one junction where that particular difference shows up. Assume that there will be, and you can be pleasantly surprised if you're wrong!
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Re: DS - 700 level - Suit [#permalink] New post 23 Jul 2011, 20:54
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fluke,

You really don't have to solve this and waste the precious time. Think about it strategically.

From 1) if Bill paid $112.5 less than the price a day before, he basically saved 25% on the suit. So it could either be July 8th or July 15th. Hence, eliminate A and D.

From 2) if Bill paid $202.5 for the suit, you can figure out the week that particular sale price was on, but not the exact date. Hence, eliminate B.

If both are true, it is easy to just pick the date which falls within the week from 2). Hence, C is correct.

No math is required except 112.5/450 which is easy 25%.

Hope this helps you.
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Re: In the table above is shown the percent reduction in the [#permalink] New post 17 Oct 2013, 06:34
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Re: In the table above is shown the percent reduction in the   [#permalink] 17 Oct 2013, 06:34
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