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Re: In the xy-coordinate plane, Is point R [#permalink]
04 Jul 2012, 19:50

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This post received KUDOS

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imhimanshu wrote:

In the xy-coordinate plane, Is point R equidistant from points (-3,-3) and (1,-3)

1. The x coordinate of point R is -1 2. Point R lies on line y = -3.

Expert, please provide your reasoning.

Thanks

Hi,

As per below diagram,

Attachment:

xy.jpg [ 11.04 KiB | Viewed 5303 times ]

All the points which lie on x=-1, will be equidistant from the given points,

Using (1), x coordinate is -1. Sufficient.

Using (2), point lies on y=-3, the point may lie anywhere on the line joining the two points, and might/might not be equidistant from two given points. Insufficient.

Re: In the xy-coordinate plane, Is point R [#permalink]
04 Jul 2012, 20:37

imhimanshu wrote:

In the xy-coordinate plane, Is point R equidistant from points (-3,-3) and (1,-3)

1. The x coordinate of point R is -1 2. Point R lies on line y = -3.

Expert, please provide your reasoning.

Thanks

The Answer should be A

1. The x coordinate of point R is -1. Which means that, the point R is (-1, y). Whatever may be the value of 'y', the two points (-3,-3) and (1,-3) will be equidistant to the point (-1,y).

The line x = -1, bisects the line joining, (-3,-3) and (1,-3), hence any point(-1,y) on this line should be of equidistant from the two points

Hence Sufficient.

2. If Point R lies on line y = -3, i.e (x,-3) it means, point R could be anywhere on the line(within the points, outside the points etc) and either way no further evidence is known to identify the value of x in (x,-3).

To be more clear,

if x=-1,Equidistant, --> Yes if x=0, Not Equidistant, -->No

Re: In the xy-coordinate plane, is point R equidistant from [#permalink]
22 Jul 2014, 15:45

cyberjadugar wrote:

imhimanshu wrote:

In the xy-coordinate plane, Is point R equidistant from points (-3,-3) and (1,-3)

1. The x coordinate of point R is -1 2. Point R lies on line y = -3.

Expert, please provide your reasoning.

Thanks

Hi,

As per below diagram,

Attachment:

xy.jpg

All the points which lie on x=-1, will be equidistant from the given points,

Using (1), x coordinate is -1. Sufficient.

Using (2), point lies on y=-3, the point may lie anywhere on the line joining the two points, and might/might not be equidistant from two given points. Insufficient.

Answer is (A),

Regards,

yes, it is better to draw a diagram to solve the problem. _________________

......................................................................... +1 Kudos please, if you like my post

Re: In the xy-coordinate plane, is point R equidistant from [#permalink]
02 Oct 2015, 00:49

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: In the xy-coordinate plane, is point R equidistant from [#permalink]
12 Nov 2015, 18:03

statement 1 is sufficient, because wherever we put point R, it will be equidistant from the both points. statement 2 is insufficient, since point R can be on -1;-3 which will be a point equidistant from the 2 original ones, or -2;-3 which is not equidistant.

Re: In the xy-coordinate plane, is point R equidistant from [#permalink]
15 Nov 2015, 09:51

Expert's post

Forget conventional ways of solving math questions. In DS, Variable approach is the easiest and quickest way to find the answer without actually solving the problem. Remember equal number of variables and independent equations ensures a solution.

In the xy-coordinate plane, is point R equidistant from points (-3,-3) and (1,-3)

(1) The x coordinate of point R is -1 (2) Point R lies on line y = -3.

We get a graph as below:

Attachment:

GCDS inhimanshu In the xy-coordinate plane (20151113).jpg [ 16.17 KiB | Viewed 183 times ]

In other words, it is asking whether point R is in the same distance from (-3,-3) and (1,-3). The line x=-1 is in the same distance from the points, so the x-coordinate of R has to be -1. So condition 1 is sufficient, making the answer A.

Once we modify the original condition and the question according to the variable approach method 1, we can solve approximately 30% of DS questions. _________________

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