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# In the xy plane, does the line with equation y=3x+2 contain

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In the xy plane, does the line with equation y=3x+2 contain [#permalink]

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26 Apr 2006, 01:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In the xy plane, does the line with equation y=3x+2 contain the point (r,s)?

1) (3r+2-s) (4r+9-s)=0
2) (4r-6-s) (3r+2-s)=0
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26 Apr 2006, 01:44
D...

From the first equation we get

s=3r+2 (this satisfies the GIVEN equation y=3x+r for the values (r,s))
OR
s=4r+9

From seconds equation, we get
s=4r+6
OR
s=3r+2 (this again satisfies)

Combining option 1 AND option 2,
the only soilution that is common is s=3r+2

Hence, it satisfies!
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29 Apr 2006, 18:33
sm176811 wrote:
D...

From the first equation we get

s=3r+2 (this satisfies the GIVEN equation y=3x+r for the values (r,s))
OR
s=4r+9

From seconds equation, we get
s=4r+6
OR
s=3r+2 (this again satisfies)

Combining option 1 AND option 2,
the only soilution that is common is s=3r+2

Hence, it satisfies!

thanks for the explaination.
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08 May 2006, 21:43
OA is C... what gives?
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08 May 2006, 23:06
why do you say:

{Combining option 1 AND option 2,
the only soilution that is common is s=3r+2

Hence, it satisfies!

If we need to combine them to eliminate the OR's, then the correct answer should be C.
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08 May 2006, 23:12
[quote="stevenzeng"]OA is C... what gives?[/quote]

see my other post. It's C because you need to combine the information to eliminate the OR. The stmts by themselves do not say definitely that the line contains the points.

There's a key to DS problems: Remember that just because you can't say Yes, doesn't mean you can't say NO. I may not be able to say yes to "does x > 0", for example, but one of the stmts may give me enough information to say it definitely is NOT > 0. That's Sufficient.
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09 May 2006, 10:27
sm176811 wrote:
D...

From the first equation we get

s=3r+2 (this satisfies the GIVEN equation y=3x+r for the values (r,s))
OR
s=4r+9

From seconds equation, we get
s=4r+6
OR
s=3r+2 (this again satisfies)

Combining option 1 AND option 2,
the only soilution that is common is s=3r+2

Hence, it satisfies!

If you combine them then automatically the answer choice is C
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09 May 2006, 11:25
Would somebody mind explaining how the answer choices fit into what the question is asking? I really don't understand this one...

The way I see it, wouldn't either answer choice be sufficient? Why the need to combine it?
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10 May 2006, 02:48
stevenzeng wrote:
Would somebody mind explaining how the answer choices fit into what the question is asking? I really don't understand this one...

The way I see it, wouldn't either answer choice be sufficient? Why the need to combine it?

1) (3r+2-s) (4r+9-s)=0

S can have 2 values -
s = 3r + 2 or s = 4r + 9

If s=3r + 2, it satisfies the eq, but for s = 4r + 9, it does not.

Hence insufficient

2) (4r-6-s) (3r+2-s)=0

Here s can have 2 values.
s=4r-6 or s=3r+2

If s=3r + 2, it satisfies the eq, but if s=4r-6, it does not.

Hence insuff

Taking these two together, the only common value of s = 3r+2. This satisfies the eq. Hence sufficient.
Hence C.

Hope it is clear now.
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11 May 2006, 09:38
However,

Anything multiplied by (3r+2-s) is ZERO, right! Doesn't it mean each of them is sufficient on its own?
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11 May 2006, 20:06
techno123 wrote:
However,

Anything multiplied by (3r+2-s) is ZERO, right! Doesn't it mean each of them is sufficient on its own?

Yes, my thoughts exactly too. Is there different way we can look at and understasnd this problem?

Thanks..
11 May 2006, 20:06
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