In the xy-plane, if line k has negative slope and passes : GMAT Data Sufficiency (DS) - Page 2
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# In the xy-plane, if line k has negative slope and passes

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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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04 Mar 2013, 03:38
slope and algebraic

I want to follow this posting.

this type of hard question appear in gmatprep but dose not appear in og.
VP
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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04 Mar 2013, 03:47
this type of question appear infrequently and so become hard questions.

never use drawings. use algebraic
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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06 Jun 2013, 23:43
In the xy-plane, if line k has negative slope and passes through the point (-5,r) , is the x-intercept of line k positive?

(1) The slope of line k is -5.
(2) r > 0

the answer is E only because : as per your assumption you took x intercept as x.but it can also be negative try it with -x we cannot determine the sign of x intercept.if x intercept is (-x,0) then slope m=r-0/-5+x.
and x=r+5m/m..
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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05 Dec 2014, 22:09
(1) the slope of line k is -5 => we know for each unit of "run" the line should have 5 units of "fall" => the x-intercept to be positive we should have r>25 but here the value of r is not clear => insufficient.
(2) r>0, same as (1) the value of r is not clear also we don't know the slope => insufficient.
(1) & (2): we know the slope is -5 and r>0 but r can be greater than 25 or less than it. => insufficient.
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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24 Dec 2015, 06:56
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Re: In the xy-plane, if line k has negative slope and passes [#permalink]

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25 Sep 2016, 03:29
In the xy-plane, if line k has negative slope and passes through the point (-5,r) , is the x-intercept of line k positive?

(1) The slope of line k is -5.
(2) r > 0

Hi,
Can you please tell where I am wrong.
I assumed eq of line as y=mx+c.
Let x intercept be A(x,0)
At point A,
0=mx+c
=>x=-c/m
Hence, sign of x will depend on sign of c/m
Since m is negative,
i. if c<0, -c/m <0 =>x<0
ii. if c>0, -c/m >0 =>x>0

Statement 1 is not sufficient.
As per statement 2, r>0
=> -5m+c>0
=>-5m>-c
=>5m<c
=>5<c/m or c/m >5
=> both c and m have same sign i.e. m,c<0
=> x<0
=> Statement 2 is sufficient
Re: In the xy-plane, if line k has negative slope and passes   [#permalink] 25 Sep 2016, 03:29

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