In the xy-plane, line l and line k intersect at the point : DS Archive
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In the xy-plane, line l and line k intersect at the point

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In the xy-plane, line l and line k intersect at the point [#permalink]

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10 Oct 2008, 09:36
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In the xy-plane, line l and line k intersect at the point (16/5, 12/5). What is the slope of line l?
(1) The product of the slopes of line l and line k is –1.
(2) Line k passes through the origin.
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10 Oct 2008, 09:43
vksunder wrote:
In the xy-plane, line l and line k intersect at the point (16/5, 12/5). What is the slope of line l?
(1) The product of the slopes of line l and line k is –1.
(2) Line k passes through the origin.

(1) Tells us that the two lines are perpendicular. But it does not help us to find the slope of line l. So not suff.

(2) tells us that apart from (16/5,12/5), line k passes through origin (0,0). But no info about line l. So not suff.

When combined. (2) helps us find the slope of k. and (1) helps us find the slope of l using the slope of k (slope l *slope k =-1).

So C
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10 Oct 2008, 09:48
amitdgr wrote:
vksunder wrote:
In the xy-plane, line l and line k intersect at the point (16/5, 12/5). What is the slope of line l?
(1) The product of the slopes of line l and line k is –1.
(2) Line k passes through the origin.

(1) Tells us that the two lines are perpendicular. But it does not help us to find the slope of line l. So not suff.

(2) tells us that apart from (16/5,12/5), line k passes through origin (0,0). But no info about line l. So not suff.

When combined. (2) helps us find the slope of k. and (1) helps us find the slope of l using the slope of k (slope l *slope k =-1).

So C

Agree !

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10 Oct 2008, 10:05
So when you map out the line K, the diagram would look similar to:

Correct?
Attachments

clarify.jpg [ 19.37 KiB | Viewed 700 times ]

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10 Oct 2008, 10:07
How did you derive this part from stat 1: "Tells us that the two lines are perpendicular"
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10 Oct 2008, 10:18
vksunder wrote:
How did you derive this part from stat 1: "Tells us that the two lines are perpendicular"

lines are perpendicular if and only if the product of their slopes is -1.

Re: DS   [#permalink] 10 Oct 2008, 10:18
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