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# In the xy-plane, line l and line k intersect at the point

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Manager
Joined: 22 Jul 2008
Posts: 94
Location: Bangalore,Karnataka
Followers: 3

Kudos [?]: 160 [0], given: 11

In the xy-plane, line l and line k intersect at the point [#permalink]

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05 Jan 2010, 08:00
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35% (medium)

Question Stats:

73% (01:40) correct 27% (00:56) wrong based on 68 sessions

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In the xy-plane, line l and line k intersect at the point (16/5, 12/5). What is the slope of line l?

(1) The product of the slopes of line l and line k is –1.
(2) Line k passes through the origin.
[Reveal] Spoiler: OA
Verbal Forum Moderator
Joined: 02 Aug 2009
Posts: 4096
Followers: 287

Kudos [?]: 2970 [0], given: 100

Re: In the xy-plane, line l and line k intersect at the point [#permalink]

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05 Jan 2010, 08:14
C..
si) gives us the relation in two lines ..the two r perpendicular to each other...not suff
sii) it gives us the 2nd pt on line k... we can find the slope of k from it but not l.. not suff.
combined frm k ,slope of l can be found frm reln in si..suff
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Manager
Joined: 24 Aug 2016
Posts: 64
Location: India
WE: Information Technology (Computer Software)
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Kudos [?]: 8 [0], given: 10

Re: In the xy-plane, line l and line k intersect at the point [#permalink]

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04 Oct 2016, 22:50
Let equation of line l --> $$y = Lx + a$$
Let equation of line K --> $$y = Kx + b$$

Both line passes through (16/5, 12/5)

$$16L+5a = 12$$ --Eq 1
$$16K+5b = 12$$ --Eq2

(1) The product of the slopes of line l and line k is –1.

$$L * K=-1$$ --Eq3

We have 3 equation and 4 unknown (a,b,L, M). -- Not sufficient

(2) Line k passes through the origin.

$$b = 0$$
$$16K+5b = 12$$ ==> $$16K= 12$$ ==> $$\frac{3}{4}$$ -- Not sufficient

When we combine (1) and (2), L = -$$\frac{4}{3}$$ --Sufficient.

Ans C.
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Re: In the xy-plane, line l and line k intersect at the point   [#permalink] 04 Oct 2016, 22:50
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