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In the xy plane, point P has coordinates (a,b) and point Q

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In the xy plane, point P has coordinates (a,b) and point Q [#permalink] New post 18 Sep 2006, 17:22
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GMAT Prep provides C as the answer to the following question. Could someone please explain in detail?

In the xy plane, point P has coordinates (a,b) and point Q has coordinates (c,d). What is the distance between P and Q?

(1) b-d=4
(2) a-c=3
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Re: GMAT Prep DS [#permalink] New post 18 Sep 2006, 18:01
wshaffer wrote:
GMAT Prep provides C as the answer to the following question. Could someone please explain in detail?

In the xy plane, point P has coordinates (a,b) and point Q has coordinates (c,d). What is the distance between P and Q?

(1) b-d=4
(2) a-c=3


each hint tells you how far x1 is from x2 and y1 from y2

that way you can draw a right triangle and using pythagorean theorem calculate the hypotenuse-distance between two points.

you can pick (0,0) for point P and draw on the paper
so Q=(-3,-4), so length of side1 = 4 and side2=3, so hyp=5
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 [#permalink] New post 18 Sep 2006, 22:37
Distance between two points (x1,y1) and (x2,y2) in 2-d plane
= sqrt((x2-x1)2 + (y2-y1)2))

plug in the value and u'll get the distance.
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 [#permalink] New post 19 Sep 2006, 12:59
Still scratchin my head. Do we really need to know formula which gives distance b/w two points?
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 [#permalink] New post 19 Sep 2006, 14:12
Yes, I would use distance formula too.
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 [#permalink] New post 19 Sep 2006, 14:35
Distance formula for a co-ordinate plane is :

sqrt( (x1-x2)^2 + (y1-y2)^2)

If we know (b-d) and (a-c) it is sufficient.
  [#permalink] 19 Sep 2006, 14:35
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In the xy plane, point P has coordinates (a,b) and point Q

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