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Re: In the xy-plane, region R consists of all the points (x, y) [#permalink]
17 Dec 2012, 11:10

look, the question is about the point (r,5) not the point (r,s). if the question was about the point (r,s), I think the (2) is sufficient, the correct answer is B However, if the question is about the point (r,5), (1) and (2) together are sufficient but none of them alone is sufficient. The corrent answer is C

Re: In the xy-plane, region R consists of all the points (x, y) [#permalink]
26 Feb 2013, 23:44

I want to follow this posting.

this question test out ability to react to numbers, to plug in number. This process is done by Bruno already. og explanation is the same. this process of plugging takes me 2 minutes.

drawing or solving the equation is too time consuming and is not the correct the method.

Re: In the xy-plane... [#permalink]
27 Sep 2013, 10:26

Bunuel wrote:

shreya717 wrote:

This is how I solved the question and im arriving at the wrong answer. Please could someone correct me.

Given:- equation of the line is 2x+3y<6 Thus, y<2/3x+2 the y and x intercepts of the given line are y<2 and x <3 respectively.

Statement 2 gives us that r (x) < 2 and s (y) <3. Therefore i concluded statment 2 is suff to answer the question. Am i going wrong in the calculation?

Thanks.

First of all 2x+3y\leq{6} can be rewritten as y\leq{2-\frac{2}{3}*x}, not as y\leq{2+\frac{2}{3}*x}. Next, it's not equation of a line, it gives the region which is below line y={2-\frac{2}{3}*x}, so all your farther conclusions are wrong.

Thanks for the explanation. I used the same incorrect approach to get to B and I missed that the equation defines a region and not a line.

If the equation was a line, then would "B" be the correct answer?

Re: In the xy-plane... [#permalink]
30 Sep 2013, 22:37

Expert's post

Bunuel wrote:

metallicafan wrote:

In the xy-plane, region R consists of all the points (x, y) such that 2x + 3y =< 6 . Is the point (r,s) in region R?

(1) 3r + 2s = 6 (2) r=< 3 and s=< 2

Though the solution provided by shrouded1 above is perfectly OK, it's doubtful that can be done in 2-3 minutes.

So I'd say the best way for this question would be to try boundary values.

Q: is 2r+3s\leq{6}?

(1) 3r + 2s = 6 --> very easy to see that this statement is not sufficient: If r=2 and s=0 then 2r+3s=4<{6}, so the answer is YES; If r=0 and s=3 then 2r+3s=9>6, so the answer is NO. Not sufficient.

(2) r\leq{3} and s\leq{2} --> also very easy to see that this statement is not sufficient: If r=0 and s=0 then 2r+3s=0<{6}, so the answer is YES; If r=3 and s=2 then 2r+3s=12>6, so the answer is NO. Not sufficient.

(1)+(2) We already have an example for YES answer in (1) which valid for combined statements: If r=2<3 and s=0<2 then 2r+3s=4<{6}, so the answer is YES; To get NO answer try max possible value of s, which is s=2, then from (1) r=\frac{2}{3}<3 --> 2r+3s=\frac{4}{3}+6>6, so the answer is NO. Not sufficient.

Answer: E.

Hope it's clear.

Hi Bunuel, Just a quick clarification- Combining two statements, to get NO as answer, we can also try the first values from Stat.1 - If r=0 and s=3 then 2r+3s=9>6, so the answer is NO..

Re: In the xy-plane... [#permalink]
30 Sep 2013, 23:13

Expert's post

bagdbmba wrote:

Bunuel wrote:

metallicafan wrote:

In the xy-plane, region R consists of all the points (x, y) such that 2x + 3y =< 6 . Is the point (r,s) in region R?

(1) 3r + 2s = 6 (2) r=< 3 and s=< 2

Though the solution provided by shrouded1 above is perfectly OK, it's doubtful that can be done in 2-3 minutes.

So I'd say the best way for this question would be to try boundary values.

Q: is 2r+3s\leq{6}?

(1) 3r + 2s = 6 --> very easy to see that this statement is not sufficient: If r=2 and s=0 then 2r+3s=4<{6}, so the answer is YES; If r=0 and s=3 then 2r+3s=9>6, so the answer is NO. Not sufficient.

(2) r\leq{3} and s\leq{2} --> also very easy to see that this statement is not sufficient: If r=0 and s=0 then 2r+3s=0<{6}, so the answer is YES; If r=3 and s=2 then 2r+3s=12>6, so the answer is NO. Not sufficient.

(1)+(2) We already have an example for YES answer in (1) which valid for combined statements: If r=2<3 and s=0<2 then 2r+3s=4<{6}, so the answer is YES; To get NO answer try max possible value of s, which is s=2, then from (1) r=\frac{2}{3}<3 --> 2r+3s=\frac{4}{3}+6>6, so the answer is NO. Not sufficient.

Answer: E.

Hope it's clear.

Hi Bunuel, Just a quick clarification- Combining two statements, to get NO as answer, we can also try the first values from Stat.1 - If r=0 and s=3 then 2r+3s=9>6, so the answer is NO..

Please correct me if I'm wrong.

When combining the values must satisfy both statements: r=0 and s=3 does not satisfy the second one. _________________

Re: In the xy-plane, region R consists of all the points (x, y) [#permalink]
08 Jul 2014, 12:58

gmat1220 wrote:

Bunuel, Thanks for the solution ! Please correct me.

If (r,s) is inside the region R on the XY plane, as per equation 2r + 3s <=6 is true. That also means that r is bounded (when s=0) i.e. r<=3 s is also bounded (when r=0) is s<=2

Hence r<=3 and s<=2 should be sufficient. Am I missing something? Please clarify.

I made the same mistake as you and marked B. But the region enclosed by the second statement is a rectangular region where r < = 3 and s<= 2. Only some part of this rectangle lies below the original line 2x + 3y <= 6. So this option is not sufficient to say that all points (r,s) lie below the original line. Others have shown this via algebra.

gmatclubot

Re: In the xy-plane, region R consists of all the points (x, y)
[#permalink]
08 Jul 2014, 12:58