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Region R essentially means all the points on the line 2x + 3y = 6. If, I plot this line in XY plane, it will meet X-axis at (3,0) and Y-axis at (0,2).
Now stmt1 gives a line that meets X-axis at (2,0) and Y-axis at (0,3). This line definitely intersects the original line at one point. Hence, this is insufficient as only for one combination of r and s, this satisfies the original equation. For other combinations, it does not.
stmt 2: this is a point clearly not on the original line. Hence, sufficient.
In the xy-plane, region R consists of all the points (x, y) such that 2x + 3y = 6. Is the point (r, s) in region R ? (1) 3r + 2s = 6 (2) r = 3 and s = 2
Looks like we are missing something in this question..
region R consists of all the points (x, y) such that 2x + 3y = 6 -- this is line not a region.. so I believe we are missing <= or >= then it may be region. ( 2x + 3y <= 6 or 2x + 3y >= 6 represents region) _________________
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The equation 2x + 3y = 6 represent the line, it can not represent the region........ question itself might be wrong.....however it appeared to me as it is and that's why i could not understood it. the source is unknowm (some papers in PDF Form)
Last edited by vivektripathi on 18 Sep 2008, 09:47, edited 1 time in total.