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# In this problem basically asking if Carlos rate > 12

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04 Oct 2007, 08:53
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In this problem basically asking if Carlos rate > 12 miles/hr

1. after calc rate >10.something
2 after calc rate <12.something miles/hr

Am I reqd to do that to solve such problems.

Quicker way? - am i missing something here
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Last edited by lnaik on 05 Oct 2007, 10:13, edited 2 times in total.
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05 Oct 2007, 08:02
The attachment doesn't match your question.

Thanks

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05 Oct 2007, 08:06
sorry. I am heading out to lunch but will post the question when I get back.
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05 Oct 2007, 16:36
I remember getting this one

D
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05 Oct 2007, 22:22
[quote="lnaik"]In this problem basically asking if Carlos rate > 12 miles/hr

1. after calc rate >10.something
2 after calc rate <12> we will call this distance x so is x>31680?

S1: 16ft/s< is carlo's rate. well it could be 16.0000000000001ft/s or

20ft/s. Just try 16ft per/sec to get the idea where its at. We get 30min*60sec ---> 1800 sec. 1800*16=28800ft. So the real distance or x is going to be a lot greater or it could be just a little bit greater than 28800ft.

Insuff.

S2: 18ft/s > carlo's rate. Again use 18ft/s as a benchmark b/c it could be 17.999999999999999999999 or 1 ft/s.

18*1800= 32400. So it could be a little less than 32400 or a lot less than 32400. Insuff.

Essentially the faster carlo's goes the greater the distance.

1&2:

now we can make an inequality for x. 28800<x<32400>31680. But we don't know anything else than the above info.

So E it is.
Re: GMATPrep 2   [#permalink] 05 Oct 2007, 22:22
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