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# In Town X, 64 percent of the population are employed, and 48

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In Town X, 64 percent of the population are employed, and 48 [#permalink]  16 Nov 2009, 15:25
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In Town X, 64 percent of the population are employed, and 48 percent of the population are employed males. What percent of the employed people in Town X are females?

(A) 16%
(B) 25%
(C) 32%
(D) 40%
(E) 52%
[Reveal] Spoiler: OA
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Re: Never underestimate any questions [#permalink]  16 Nov 2009, 16:27
ezinis wrote:
In Town X, 64 percent of the population are employed,
and 48 percent of the population are employed males.
What percent of the employed people in Town X are
females?
(A) 16%
(B) 25%
(C) 32%
(D) 40%
(E) 52%

male-employed - 64%
female-employed-16%
Total employed 64%

means total unemployed = 36%

therefore d and e are not correct because female unemployed has to be less than 36%

female-unemployed = 32% male unemployed = 4%
48% + 4% = 52%
16% + 32% = 48%

plug in a and b in place of 32% and the sum is not 100%

16/64 =25

Last edited by lagomez on 16 Nov 2009, 16:56, edited 1 time in total.
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Re: Never underestimate any questions [#permalink]  16 Nov 2009, 16:50
Expert's post
lagomez wrote:

male-employed - 64%
female-employed-16%
Total employed 64%

means total unemployed = 36%

therefore d and e are not correct because female unemployed has to be less than 36%

female-unemployed = 32% male unemployed = 4%
48% + 4% = 52%
16% + 32% = 48%

plug in a and b in place of 32% and the sum is not 100%

I think we are asked to calculate the percentage of females in employed people.

Total employed people 64%, out of which 48 are male, hence 16% are employed females. 16/64=1/4=25%

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Re: Never underestimate any questions [#permalink]  16 Nov 2009, 16:57
Bunuel wrote:
lagomez wrote:

male-employed - 64%
female-employed-16%
Total employed 64%

means total unemployed = 36%

therefore d and e are not correct because female unemployed has to be less than 36%

female-unemployed = 32% male unemployed = 4%
48% + 4% = 52%
16% + 32% = 48%

plug in a and b in place of 32% and the sum is not 100%

I think we are asked to calculate the percentage of females in employed people.

Total employed people 64%, out of which 48 are male, hence 16% are employed females. 16/64=1/4=25%

made the changes to my original post...you are correct..got the same percentage but i have no idea why i was going for female unemployed..totally off my game.

had my mind on something else i guess
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Re: Never underestimate any questions [#permalink]  16 Nov 2009, 22:12
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In problems like this one I always like to use tables to organize my thoughts. First I assumed that there are a 100 people in this town (for me it just makes it mentally easier).

.................EMPLOYED........NOT EMPLOYED
MALE..............48......................B.............
FEMALE...........C.......................D............
TOTALS..........64......................36...............100

We are given the value of Employed + Male = 48 and the value of the Total Employed = 64.

So as we can see it is pretty easy to find the number of Employed + Females: 64-48=C or 16.

16/64 = 25%

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Re: OG12- PS124 [#permalink]  09 May 2010, 20:53
So reading the question very carefully 48% of the population are employed males and 64 % of the population are employed.

What percent of the employed are females? The percent employed females in the total population is easy. That is 16%. 64 minus 48. But they are asking what percent of the employed are female. Now we must compare that 16% to the total employed 16/64. So one quarter of the employed are female.

B) 25% should be correct
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Re: OG12- PS124 [#permalink]  18 May 2010, 15:22
here total employed population is 64% and 48 % of the total population is males so the 16 % of the population is employed is females so the % of females employees out of employed males is( 16/64)*100 = 25%
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Re: Percentage -Population [#permalink]  26 Aug 2010, 07:06

Lets say the town's population is 100
64 employed (given)
48 employed males (given)
64 - 48 = 16 employed females

the question is :
what percentage of employed ppl are females

therefore,

16 in 64 -> how many in 100.
Solving... 25
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Re: Percentage -Population [#permalink]  26 Aug 2010, 23:23
Question does not seem to have adequate information. Since we dont know how many unempolyed males are there.
Solution given by piyatiwari does not cosider this fact.
Also would like to know the source of this problem
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Re: Percentage -Population [#permalink]  27 Aug 2010, 04:46
prashantbacchewar wrote:
Question does not seem to have adequate information. Since we dont know how many unempolyed males are there.
Solution given by piyatiwari does not cosider this fact.
Also would like to know the source of this problem

We don't need to know number of unemployed males. The question has all the required information.

The problem is from OG, I guess.
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Re: Never underestimate any questions [#permalink]  23 Sep 2010, 06:56
It will be easier if you rephrased the the question like: how many percent female out of the employed people.

Most people will jump to answer A (16%) because it accidentally looks like the number they just solved half way. have fun guys.
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Re: Never underestimate any questions [#permalink]  08 Nov 2010, 22:25
Explanation:
Suppose, Population= P, Employed People= E , Employed Male= M, and Employed Female= F. What we need to find is $$\frac{Employed Female}{Employed People} %=\frac{F}{E} %$$

Let's pick $$100$$ as a smart number here for the population of town X.

So, $$P= 100$$ and
$$E= 64% of P = \frac{64}{100} * 100 = 64$$
$$M= 48% of P = \frac{48}{100} * 100 = 48$$
Then, $$F= E - M = 64 - 48 = 16$$
Therefore, from above we can calculate that,
$$\frac{F}{E} % = \frac{16}{64} * 100 = \frac{1}{4} * 100 = 25 %$$ (we got what we were asked to find )

Be careful not to get into the trap of finding employed female percentage of population of town X because we are asked to find what percent of the employed people ($$x% of E$$) are female ($$F$$), try to translate the words--> $$x% of E = F$$ --> $$x=F/E %= ?$$ and clearly state what exactly needs to be found in your own words or expression.
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Re: Never underestimate any questions [#permalink]  15 Mar 2011, 21:17
Let total population = P and Employed People = E

So 0.64P = E

and 0.48P = Male

So 0.64P - 0.48P = 0.16P are employed females

So 0.16P/0.64P = 25%

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Re: Never underestimate any questions [#permalink]  15 Mar 2011, 22:04
ezinis wrote:
In Town X, 64 percent of the population are employed,
and 48 percent of the population are employed males.
What percent of the employed people in Town X are
females?
(A) 16%
(B) 25%
(C) 32%
(D) 40%
(E) 52%

Total population 100
total employed 64
employed male 48 (given)
employed female 64-48= 16
percentage of female employed people to total employed people: 16/64*100=25%
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]  23 Sep 2013, 21:07
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]  24 Sep 2014, 06:33
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Re: In Town X, 64 percent of the population are employed, and 48 [#permalink]  24 Sep 2014, 22:49
Total Employed (Male + Female) = 64

Male Employed = 48

So, remaining Female employed = 64 - 48 = 16

Percentage$$= \frac{16}{64} * 100 = 25%$$

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Re: In Town X, 64 percent of the population are employed, and 48   [#permalink] 24 Sep 2014, 22:49
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