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In triangle ABC angle ABC is 90 degrees. What is the [#permalink]

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11 Oct 2008, 07:02

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In triangle ABC angle ABC is 90 degrees. What is the perimeter of the triangle ABC?

a:ab+bc=7 b: ab/bc =3/4

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient

A alone is not sufficient? as it is right angle triangle and B is 90..means AB and BCmust be 3 and 4 or 4 and 3?

In triangle ABC angle ABC is 90 degrees. What is the perimeter of the triangle ABC?

a:ab+bc=7 b: ab/bc =3/4

Statement (1) ALONE is sufficient, but Statement (2) ALONE is not sufficient Statement (2) ALONE is sufficient, but Statement (1) ALONE is not sufficient BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient Statements (1) and (2) TOGETHER are NOT sufficient

A alone is not sufficient? as it is right angle triangle and B is 90..means AB and BCmust be 3 and 4 or 4 and 3?

Thanks

A is not suff. It can be 1+6 , 2+5, 3+4 _________________

"You have to find it. No one else can find it for you." - Bjorn Borg

Vishal I think you may want to check again with the ratio 3:4:5. As I remember, a triangle that has its sides with ratio 3:4:5 usually could be right triangle. This is often used as a tip to solve the difficult calculation of sides' lengths rather than a definition of right triangle.

Given AB=2, BC=5, then according to Pithagor formular, we will have AC=sqrt(AB^2+BC^2)=sqrt29. We quite can draw such a triangle.

Vishal I think you may want to check again with the ratio 3:4:5. As I remember, a triangle that has its sides with ratio 3:4:5 usually could be right triangle. This is often used as a tip to solve the difficult calculation of sides' lengths rather than a definition of right triangle.

Given AB=2, BC=5, then according to Pithagor formular, we will have AC=sqrt(AB^2+BC^2)=sqrt29. We quite can draw such a triangle.

Guys.. Why cant side 1 + side 2 = 7 be 1 + 6 = 7 ?? The third side will be 1^2 + 6^2 = 37

the third side can be SQRT(37). So what if the third side is not a positive integer ?? Pythogoras theorem does not mandate that all three sides are integers. _________________

"You have to find it. No one else can find it for you." - Bjorn Borg