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In triangle ABC, point X is the midpoint of side AC and

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In triangle ABC, point X is the midpoint of side AC and [#permalink] New post 26 Dec 2008, 23:33
In triangle ABC, point X is the midpoint of side AC and point Y is the midpoint of side BC. If point R is the midpoint of line segment XC and if point S is the midpoint of line segment YC. What is the area of the triangular region RCS?

A. the area of the triangular region ABX is 32
B. The length of one of the altitudes of triangular ABC is 8

Last edited by shobuj40 on 27 Dec 2008, 23:40, edited 1 time in total.
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Re: Triangle [#permalink] New post 27 Dec 2008, 03:12
Is it A

A)
The first hint in the length equalities.
So, A(ABX) = A(BXC) = 32
YR splits BXC into 2 equal halves, so A(YRC) = 16
SR splits YC into 2 equal halves, so A(SRC) = 4

B) altitude is insufficient since we do not anything about the type of the triangle ABC.
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Re: Triangle [#permalink] New post 27 Dec 2008, 04:38
ampok

How can YR split BXC in two equal halves
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Re: Triangle [#permalink] New post 28 Dec 2008, 14:56
shobuj40 wrote:
ampok

How can YR split BXC in two equal halves


I think he meant YX will split BXC into two halves. A(YXC)= 8

Again YR will divide XYC into two halves A(YRC)=4

SR will divide YRC into two halves A(RCS)=2
Re: Triangle   [#permalink] 28 Dec 2008, 14:56
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In triangle ABC, point X is the midpoint of side AC and

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