Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

In triangle ABC above, what is the length of side BC?

As <BDC=<BCD then the BD=BC. Also as <ADB=180-2x (exterior angle) and the sum of the angles of a triangle is 180 degrees then in triangle ADB we'll have: x+(180-2x)+<ABD=180 --> <ABD=x. Now, we have that <ABD=x=<DAB so AD=BD --> AD=BD=BC.

Question: BC=?

(1) Line segment AD has length 6 --> AD=BD=BC=6. Sufficient. (2) x = 36 --> we know only angles which is insufficient to get the length of any line segment.

the one point that puzzles me is how did you get /BAD = x ?

It's given that <BAD=x degrees (refer to the diagram in my first post on the page). Some OG books have a typo missing this info (as in vibhav post).
_________________

The question asks the length of side BC. From the figure, you can see that triangle BDC is an isosceles triangle with BD = BC. Thus, to know the length of BC, it is okay if we know the length of BD.

Statement 1: To solve such problems, you have to know that in a triangle, the measure of the exterior angle is equal to the sum of the two non-adjacent angles of the triangle.

That is, in the given figure, for triangle ABD, angle BDC is the exterior angle. Thus, BDC = ABD + BAD That is, 2x = ABD + x. Thus ABD = x.

Now, you can see that triangle ABD is an isosceles triangle in which AD = BD = 6. Thus, BD = BC = 6. SUFFICIENT

Statement 2: x = 36 does not tell you anything about the length of any side. INSUFFICIENT

Using Similar triangles we know that 1) BD = BC (angle BDC = angle BCD) 2) We know angle BDA = 180-2x which means angle ABD = x 3) So, from the second similar triangle we know that angle BAD = angle ABD = x 4) Using similar triangles again; AD = BD 5) Combing 1 and 4; AD = BD = BC.

Why is AD=BD=BC? If AD is opposite to X, BD opposite to X as well and BC opposite to 2x? Shouldn't BC be larger than both or equal to both TOGETHER?

Thanks for clarifying

Cheers! J

Yes but they are sides of different triangles. Note that by the same logic, BD is opposite to 2x as well. The point is that it is opposite to x in one triangle (ABD) and opposite to 2x in another triangle (BDC).

BC will be equal to BD because they are both opposite 2x in triangle BDC.

AD will be equal to BD because they are both opposite angle x in triangle ABD.

Re: In triangle ABC above, what is the length of side BC? [#permalink]

Show Tags

20 Jun 2014, 02:35

Bunuel wrote:

Attachment:

trig2uc8.png

In triangle ABC above, what is the length of side BC?

As <BDC=<BCD then the BD=BC. Also as <ADB=180-2x (exterior angle) and the sum of the angles of a triangle is 180 degrees then in triangle ADB we'll have: x+(180-2x)+<ABD=180 --> <ABD=x. Now, we have that <ABD=x=<DAB so AD=BD --> AD=BD=BC.

Question: BC=?

(1) Line segment AD has length 6 --> AD=BD=BC=6. Sufficient. (2) x = 36 --> we know only angles which is insufficient to get the length of any line segment.

Answer: A.

Thanks for the answer... I guess I need to expand my thought process...
_________________

I'm happy to help if you wanna know about Ross & UMich, but please do not come to me with your GMAT issues or questions. And please add a bit of humor to your questions or you'll bore me to death.

Re: In triangle ABC above, what is the length of side BC? [#permalink]

Show Tags

08 Sep 2015, 18:20

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

In triangle ABC above, what is the length of side BC? [#permalink]

Show Tags

30 Sep 2015, 12:10

blendercroix wrote:

I'm sorry guys but the answer does not make sense at all!!

<BDC = <BCD ( I got this) <ADB = 180 - 2x (I got this) The sum of this triangle is 180

180 = x + (180-2x) + <ABD

now I'm confused. How did you come up with <ABD is equal to x??????? Even if we substitute <ABD with x, thus would be:

180 = x + 180-2x + x 180 = 2x -2x +180 180 = 180

The sum of two non-adjacent interior angles of a triangle is always equal to the measure of an exterior angle of a triangle. Even if you didn't know this property, say <ABD is y, so now we have <BAD is x, <ABD is y and <BDA is 180-2x. The sum of the interior angles of a triangle must sum to 180 degrees. So we have x+y+180-2x=180-->y=x

Re: In triangle ABC above, what is the length of side BC? [#permalink]

Show Tags

08 Oct 2015, 10:26

Just another take on the question. Experts can correct me.

< BAD is x and < BDC is 2x. It means triangle ABC can be considered as a triangle circumscribed in a circle with D as its center. Hence, AD = DC = DB, the radius of the circle. Also, BD = BC (opposite to equal angles.)

Hence the length of AD is enough to answer the question. Choice A
_________________

KudosPlease if you find my question / solution helpful.

Re: In triangle ABC above, what is the length of side BC? [#permalink]

Show Tags

29 Jan 2016, 10:07

Bunuel wrote:

Attachment:

trig2uc8.png

In triangle ABC above, what is the length of side BC?

As <BDC=<BCD then the BD=BC. Also as <ADB=180-2x (exterior angle) and the sum of the angles of a triangle is 180 degrees then in triangle ADB we'll have: x+(180-2x)+<ABD=180 --> <ABD=x. Now, we have that <ABD=x=<DAB so AD=BD --> AD=BD=BC.

Question: BC=?

(1) Line segment AD has length 6 --> AD=BD=BC=6. Sufficient. (2) x = 36 --> we know only angles which is insufficient to get the length of any line segment.

Answer: A.

Why did you assume that ADC is a straight line. Because if it isint given specifically in the question then the entire logic fails. then angle BDA and BDC are not supplementary.

gmatclubot

Re: In triangle ABC above, what is the length of side BC?
[#permalink]
29 Jan 2016, 10:07

It’s quickly approaching two years since I last wrote anything on this blog. A lot has happened since then. When I last posted, I had just gotten back from...

Since my last post, I’ve got the interview decisions for the other two business schools I applied to: Denied by Wharton and Invited to Interview with Stanford. It all...

Marketing is one of those functions, that if done successfully, requires a little bit of everything. In other words, it is highly cross-functional and requires a lot of different...