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# Indices

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Manager
Joined: 02 Sep 2008
Posts: 103
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Kudos [?]: 31 [0], given: 1

Indices [#permalink]  14 Mar 2009, 16:46
Q12:
Which of the following is equal to [1/( SQRT(3)- SQRT(2))]2
A. 1
B. 5
C. SQRT(6)
D.5 - SQRT(6)
E. 5 + 2 SQRT(6)
Intern
Joined: 14 Mar 2009
Posts: 3
Followers: 0

Kudos [?]: 0 [0], given: 0

Re: Indices [#permalink]  14 Mar 2009, 17:05
x = [1/( SQRT(3)- SQRT(2))]2
x=1^2/( SQRT(3)- SQRT(2))^2
x=1/(5-2SQRT(6))
x=[1*(5+2SQRT(6))]/[(5-2SQRT(6))*(5+2SQRT(6))]
x=(5+2SQRT(6))

Ans : E
Re: Indices   [#permalink] 14 Mar 2009, 17:05
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