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Indices [#permalink] New post 14 Mar 2009, 17:46
Q12:
Which of the following is equal to [1/( SQRT(3)- SQRT(2))]2
A. 1
B. 5
C. SQRT(6)
D.5 - SQRT(6)
E. 5 + 2 SQRT(6)
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Re: Indices [#permalink] New post 14 Mar 2009, 18:05
x = [1/( SQRT(3)- SQRT(2))]2
x=1^2/( SQRT(3)- SQRT(2))^2
x=1/(5-2SQRT(6))
x=[1*(5+2SQRT(6))]/[(5-2SQRT(6))*(5+2SQRT(6))]
x=(5+2SQRT(6))

Ans : E
Re: Indices   [#permalink] 14 Mar 2009, 18:05
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