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# inequality/abs value ds

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inequality/abs value ds [#permalink]

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16 Jan 2006, 01:44
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z is not equal to 0, is z^2/[z] < 1? []=absolute value

1) z <1
2) z >-1
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Re: inequality/abs value ds [#permalink]

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16 Jan 2006, 02:00
joemama142000 wrote:
z is not equal to 0, is z^2/[z] < 1? []=absolute value

1) z <1
2) z >-1

In order to yield a value that is less than 1, the denominator has to be greater than the numerator.

This is the case if -1<z<1, because the square of a number between -1 and 1 is smaller than the original number.

Both statement are needed in order to assure that z is between -1 and 1.

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16 Jan 2006, 02:07
C

St1: Clearly INSUFF
St2: Clearly INSUFF

Combined:

-1<z<1

square of a number less than 1 and greater than 0 (because its not required to consider -ve values here) is always less than that number. So z^2/[z] is always less than 1.
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

16 Jan 2006, 02:07
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# inequality/abs value ds

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