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Inequality question

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Inequality question [#permalink] New post 03 Jan 2007, 21:47
Explain please
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 [#permalink] New post 03 Jan 2007, 23:28
(E) for me :)

In p/k < 0, we must be sure that k is not equal to 0.

From 1
k could be 0, thus we could not conclude.

INSUFF.

From 2
k could be 0, thus we could not conclude.

INSUFF.

Both (1) and (2)
p - k > 0 (C)
<=> -p + k < 0 (A)

Since p + k < 0 (B), we have :
(A) + (B) <=> 2*k < 0 <=> k < 0.

Also,
(C) <=> p > k <=> p/k < 1 as k < 0
(B) <=> p < -k <=> p/k > -1 as k < 0

Thus,
-1 < p/k < 1 : it does reflect that p could be either a negative number or a positive one but superior to k.

INSUFF
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 [#permalink] New post 04 Jan 2007, 06:21
I had also got E, by picking numbers but OA is not E
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 [#permalink] New post 04 Jan 2007, 06:41
jainan24 wrote:
I had also got E, by picking numbers but OA is not E


So... What is the OA, perhaps OE? :)
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 [#permalink] New post 05 Jan 2007, 08:26
it has to be E.

Statement 1 says that P + K < 0.

Both numbers can be negative, thus P/K > 0.
Or, one number can be negative and the other can be positive, thus P/K < )

Statement 2 essentially says that P > K. Both numbers can be positive, or one number can be positive.

If you combine them, you can say that P = 0 and K = any negative number to satisfy both constraints. That would mean that P + K = 0. But, if you use P = 2 and K = -3, this also satisfies both statements and makes P/K < 0.
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 [#permalink] New post 05 Jan 2007, 08:55
don't care whatthe OA is, answer is E... here is the ultimative proof (that is, a counter example):

p=2 k =-5: st1 is true (2-5<0) and st2 is true (2-(-5)=7>0)
answer to stem is YES (p/k = -0.4 <0)

p=-2 k=-5: st1 is true (-2-5<0) and st2 is true (-2-(-5)=3>0)
answer to stem is NO (p/k = 0.4 > 0)

hence answer must be E.
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 [#permalink] New post 05 Jan 2007, 14:26
jainan24,

Is this question comming from McGrawhill GMAT one more time? :)

Would u make give us the OE & OA officially given?... Thanks :)
  [#permalink] 05 Jan 2007, 14:26
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